Neutral spike

I have only read to the following paragraph cited below. I wonder if the applicant knows about what he is writing.

Citing paragraph 106 of the patent application (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
"[0106] There is voltage across the inductor connected in series to the capacitor and there is voltage across the inductor connected in parallel to the capacitor. Since Power=voltage×current, a single power input produces two branches of electromagnetic power output, increasing the power output. In the alternative, the present disclosure may have one electromagnetic power output with less energy input."



It isn't as simple as this. If using an oscilloscope for measuring the current and voltage it will show some phase displacement between the current and voltage which means reactive power. Look at the following small videos to see how one can be misled if not knowing how the phase between the current and voltage is: Only the the resistive part consumes (transforms) energy like R in figure 8.

 0:42 
 Overunity Device Cop 2,5 ? explanation part 3. https://www.youtube.com/watch?v=yJEZMCCBV3U 9.5K views5 years ago





 1:01 
 Overunity Device Cop 2,5 ? explanation part 2. https://www.youtube.com/watch?v=Jamj3-2w0eE 10K views5 years ago





 1:00 
 
 Overunity Device Cop 2,5 ? part 1. but, https://www.youtube.com/watch?v=P_E0ck3v40Y 8K views5 years ago




The numbers without the phase shift looks like overunity which isn't the case when taking into account the phase shift. Only real power is useful in doing work. Reactive power doesn't do work except for the small active part heating the the wires and other components because of their parasitic resistance. This part caused by current doing work against the resistance is active power and not actually reactive power. This is why the power distributing companies may charge costumers for having high reactive power going through their cables which heats the power lines without transferring active power to their costumers. It's just pure loss because the wires have resistance. Resistance converts electric power into heat.

Just looked at the figures and found the description to figure 46:
"[0149] FIG. 46 illustrates an embodiment of the present disclosure that conserves light bulb energy. In a test conducted, on Nov. 16, 1998, a light bulb was installed according to the schematic disclosed in FIG. 46 and is still running seven years later.

[0150] Since Apparent Power (VA)=Current (A)×Voltage (V), the calculations below illustrate energy conservation for a 60 W light bulb. The voltage applied at the power input is 115 V. The apparent power for the Power Input Line (Line PIN) is measured at 126.5 VA. The apparent power measured for the shed motor fan is 126.5 VA and the apparent power measured for the light bulb is 65 VA. Therefore, 126 VA is measured at the input and a total of 191.5 VA is measured at the output, indicating an approximately 1.5 gain. Calculations are also shown for the energy savings for a 75W Bulb."

It is the apparent power that is increased. The apparent power is the vector sum of the real power and the reactive power which makes it always greater than or equal to the real (or active or true) power.


Source with description at: https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/ https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/

Regards
Ole

Ole,

I have had caps charge much faster in an LC tank than otherwise, but it 
could also have to do with noise in the core material as I was no using 
an air inductor.


On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
>
> Hi Mick,
>
> "If a reactive LC tank capacitor is then disconnected from the 
> reactive source then discharged to a resistive load then reconnected 
> energized back to the standing wave modality recharged disconnected 
> discharged etc.  If the reactive energy is harvested in this manner 
> are you claiming the same losses will occur as power factor correcting 
> the reactive back into real power?"
>
> Yes that's correct.
>
> Common power factor correction in AC is for eliminating the reactive 
> power that doesn't do any work but just heats the wires between the 
> power plant and the reactive load. This is expensive for the owners of 
> the power transmission lines and thus should be avoided. First storing 
> the energy in a capacitor (or inductor or battery) and then dumping it 
> to an active load will still make the power go in just one direction 
> even though it happens in pulses. The energy is then moving from the 
> source to the load. Reactive power has the energy moving to and from 
> the load and power source. The power moving between the capacitor and 
> inductor in an LC-tank is pure reactive except for the loss because of 
> the parasitic resistance in the components and wires.
>
> Regards
> Ole
>
>
> ---In [email protected], <mkjekyll@...> wrote :
>
> Ole,
>
> Disregarding the issue at hand with the patent terminology and not 
> concerning ourselves with the patent just a very high Q tank.
>
> If a reactive LC tank capacitor is then disconnected from the reactive 
> source then discharged to a resistive load then reconnected energized 
> back to the standing wave modality recharged disconnected discharged 
> etc.  If the reactive energy is harvested in this manner are you 
> claiming the same losses will occur as power factor correcting the 
> reactive back into real power?
>
>
>
> On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...> [EVGRAY] wrote
>
>>     I have only read to the following paragraph cited below. I wonder
>>     if the applicant knows about what he is writing.
>>
>>     Citing paragraph 106 of the patent application
>>     (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>     "[0106] There is voltage across the inductor connected in series
>>     to the capacitor and there is voltage across the inductor
>>     connected in parallel to the capacitor. Since
>>     Power=voltage×current, a single power input produces two branches
>>     of electromagnetic power output, increasing the power output. In
>>     the alternative, the present disclosure may have one
>>     electromagnetic power output with less energy input."
>>
>>
>>
>>     It isn't as simple as this. If using an oscilloscope for
>>     measuring the current and voltage it will show some phase
>>     displacement between the current and voltage which means reactive
>>     power. Look at the following small videos to see how one can be
>>     misled if not knowing how the phase between the current and
>>     voltage is: Only the the resistive part consumes (transforms)
>>     energy like R in figure 8.
>>
>>     0:42
>>     <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>
>>
>>           Overunity Device Cop 2,5 ? explanation part 3.
>>           <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>
>>     9.5K views5 years ago
>>     1:01
>>     <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>
>>
>>           Overunity Device Cop 2,5 ? explanation part 2.
>>           <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>
>>     10K views5 years ago
>>     1:00
>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>
>>
>>           Overunity Device Cop 2,5 ? part 1. but,
>>           <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>
>>     8K views5 years ago
>>
>>     The numbers without the phase shift looks like overunity which
>>     isn't the case when taking into account the phase shift. Only
>>     real power is useful in doing work. Reactive power doesn't do
>>     work except for the small active part heating the the wires and
>>     other components because of their parasitic resistance. This part
>>     caused by current doing work against the resistance is active
>>     power and not actually reactive power. This is why the power
>>     distributing companies may charge costumers for having high
>>     reactive power going through their cables which heats the power
>>     lines without transferring active power to their costumers. It's
>>     just pure loss because the wires have resistance. Resistance
>>     converts electric power into heat.
>>
>>     Just looked at the figures and found the description to figure 46:
>>     "[0149]FIG. 46 illustrates an embodiment of the present
>>     disclosure that conserves light bulb energy. In a test conducted,
>>     on Nov. 16, 1998, a light bulb was installed according to the
>>     schematic disclosed in FIG. 46 and is still running seven years
>>     later.
>>
>>     [0150]Since Apparent Power (VA)=Current (A)×Voltage (V), the
>>     calculations below illustrate energy conservation for a 60 W
>>     light bulb. The voltage applied at the power input is 115 V. The
>>     apparent power for the Power Input Line (Line PIN) is measured at
>>     126.5 VA. The apparent power measured for the shed motor fan is
>>     126.5 VA and the apparent power measured for the light bulb is 65
>>     VA. Therefore, 126 VA is measured at the input and a total of
>>     191.5 VA is measured at the output, indicating an approximately
>>     1.5 gain. Calculations are also shown for the energy savings for
>>     a 75W Bulb."
>>
>>     It is the apparent power that is increased. The apparent power is
>>     the vector sum of the real power and the reactive power which
>>     makes it always greater than or equal to the real (or active or
>>     true) power.
>>
>>
>>     Source with description at:
>>     https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>
>>     Regards
>>     Ole
>
>

Mick, Ole, Kone etal!  I have been thinking a lot about my Locked Rotor 
experiments and did a lot of reading to come up with a fool proof Lenz 
free motor / generator combination which is so easy to build and proof 
test! First of all you should read what we know as facts! See the 
following articles:

https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/

http://www.machineryspaces.com/direct-current-motors.html

https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes

https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be

https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be

https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened

Kone loves to play with the very powerful Neos as found at K&G Magnetics 
and shown in the video of the Ray's LENZ free generator.  What I will 
propose is very simple application of DC motor principles as read from 
the cited references. First you make your LENZ free  motor which is in 
reality a LINEAR MOTOR (Solenoid) which will give the necessary stroke 
length to drive the LINEAR generator (Coil oscillating within the drag 
free, LENZ free area of the Neo magnets).   Stroke of the solenoid is 
controlled by Hall sensor and IGBT drive switch to give an excursion 
rate (stroke) at a frequency of 60 HZ. By using a DC pulse  to drive the 
solenoid coil it is tricked into being in LOCKED ROTOR condition, thus 
no LENZ effect.  Has the light come on yet??   We know that Ray's 
generator puts out a sine wave output (AC) with no LENZ drag.  Following 
the DC motor principles as applied to the solenoid driver, you have a 
motor that is LENZ free also.  The combo should give an Over-unity 
output. Now the tricky part!  We know as Ole will agree in that when you 
switch the solenoid power to off state as magnetic flux is building 
toward saturation there will be a huge voltage spike (Neutral Spike) 
which we have to capture and not send to ground as ordinary practice in 
solid state switch design (snubber diodes)  The capture of the SPIKE 
energy (HV) which occurs naturally will be the over-unity factor here!  
Interesting concept!  Think about it!  Norm    Mick! (accumulator HV caps)!

On 11/16/2018 6:23 AM, Mick [email protected] [EVGRAY] wrote:
>
> Ole,
>
> I have had caps charge much faster in an LC tank than otherwise, but 
> it could also have to do with noise in the core material as I was no 
> using an air inductor.
>
>
> On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
>>
>> Hi Mick,
>>
>> "If a reactive LC tank capacitor is then disconnected from the 
>> reactive source then discharged to a resistive load then reconnected 
>> energized back to the standing wave modality recharged disconnected 
>> discharged etc. If the reactive energy is harvested in this manner 
>> are you claiming the same losses will occur as power factor 
>> correcting the reactive back into real power?"
>>
>> Yes that's correct.
>>
>> Common power factor correction in AC is for eliminating the reactive 
>> power that doesn't do any work but just heats the wires between the 
>> power plant and the reactive load. This is expensive for the owners 
>> of the power transmission lines and thus should be avoided. First 
>> storing the energy in a capacitor (or inductor or battery) and then 
>> dumping it to an active load will still make the power go in just one 
>> direction even though it happens in pulses. The energy is then moving 
>> from the source to the load. Reactive power has the energy moving to 
>> and from the load and power source. The power moving between the 
>> capacitor and inductor in an LC-tank is pure reactive except for the 
>> loss because of the parasitic resistance in the components and wires.
>>
>> Regards
>> Ole
>>
>>
>> ---In [email protected], <mkjekyll@...> wrote :
>>
>> Ole,
>>
>> Disregarding the issue at hand with the patent terminology and not 
>> concerning ourselves with the patent just a very high Q tank.
>>
>> If a reactive LC tank capacitor is then disconnected from the 
>> reactive source then discharged to a resistive load then reconnected 
>> energized back to the standing wave modality recharged disconnected 
>> discharged etc.  If the reactive energy is harvested in this manner 
>> are you claiming the same losses will occur as power factor 
>> correcting the reactive back into real power?
>>
>>
>>
>> On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...> [EVGRAY] wrote
>>
>>>     I have only read to the following paragraph cited below. I
>>>     wonder if the applicant knows about what he is writing.
>>>
>>>     Citing paragraph 106 of the patent application
>>>     (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>     "[0106] There is voltage across the inductor connected in series
>>>     to the capacitor and there is voltage across the inductor
>>>     connected in parallel to the capacitor. Since
>>>     Power=voltage×current, a single power input produces two
>>>     branches of electromagnetic power output, increasing the power
>>>     output. In the alternative, the present disclosure may have one
>>>     electromagnetic power output with less energy input."
>>>
>>>
>>>
>>>     It isn't as simple as this. If using an oscilloscope for
>>>     measuring the current and voltage it will show some phase
>>>     displacement between the current and voltage which means
>>>     reactive power. Look at the following small videos to see how
>>>     one can be misled if not knowing how the phase between the
>>>     current and voltage is: Only the the resistive part consumes
>>>     (transforms) energy like R in figure 8.
>>>
>>>     0:42
>>>     <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>
>>>
>>>           Overunity Device Cop 2,5 ? explanation part 3.
>>>           <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>
>>>     9.5K views5 years ago
>>>     1:01
>>>     <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>
>>>
>>>           Overunity Device Cop 2,5 ? explanation part 2.
>>>           <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>
>>>     10K views5 years ago
>>>     1:00
>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>
>>>
>>>           Overunity Device Cop 2,5 ? part 1. but,
>>>           <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>
>>>     8K views5 years ago
>>>
>>>     The numbers without the phase shift looks like overunity which
>>>     isn't the case when taking into account the phase shift. Only
>>>     real power is useful in doing work. Reactive power doesn't do
>>>     work except for the small active part heating the the wires and
>>>     other components because of their parasitic resistance. This
>>>     part caused by current doing work against the resistance is
>>>     active power and not actually reactive power. This is why the
>>>     power distributing companies may charge costumers for having
>>>     high reactive power going through their cables which heats the
>>>     power lines without transferring active power to their
>>>     costumers. It's just pure loss because the wires have
>>>     resistance. Resistance converts electric power into heat.
>>>
>>>     Just looked at the figures and found the description to figure 46:
>>>     "[0149]FIG. 46 illustrates an embodiment of the present
>>>     disclosure that conserves light bulb energy. In a test
>>>     conducted, on Nov. 16, 1998, a light bulb was installed
>>>     according to the schematic disclosed in FIG. 46 and is still
>>>     running seven years later.
>>>
>>>     [0150]Since Apparent Power (VA)=Current (A)×Voltage (V), the
>>>     calculations below illustrate energy conservation for a 60 W
>>>     light bulb. The voltage applied at the power input is 115 V. The
>>>     apparent power for the Power Input Line (Line PIN) is measured
>>>     at 126.5 VA. The apparent power measured for the shed motor fan
>>>     is 126.5 VA and the apparent power measured for the light bulb
>>>     is 65 VA. Therefore, 126 VA is measured at the input and a total
>>>     of 191.5 VA is measured at the output, indicating an
>>>     approximately 1.5 gain. Calculations are also shown for the
>>>     energy savings for a 75W Bulb."
>>>
>>>     It is the apparent power that is increased. The apparent power
>>>     is the vector sum of the real power and the reactive power which
>>>     makes it always greater than or equal to the real (or active or
>>>     true) power.
>>>
>>>
>>>     Source with description at:
>>>     https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>
>>>     Regards
>>>     Ole
>>
>
>

Norm,
 What would it take to make this into your suggested device?
 

 https://www.youtube.com/watch?v=O3psLcNbqxo https://www.youtube.com/watch?v=O3psLcNbqxo

 

 Ron

Norm,

Sounds like a Tesla oscillator powered by DC instead of air!

OK need to read links and think...

On 11/16/2018 5:55 AM, Norman Wootan [email protected] [EVGRAY] wrote:
>  
>
> Mick, Ole, Kone etal!  I have been thinking a lot about my Locked
> Rotor experiments and did a lot of reading to come up with a fool
> proof Lenz free motor / generator combination which is so easy to
> build and proof test! First of all you should read what we know as
> facts! See the following articles:
>
> https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
>
> http://www.machineryspaces.com/direct-current-motors.html
>
> https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
>
> https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
>
> https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
>
> https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
>
> Kone loves to play with the very powerful Neos as found at K&G
> Magnetics and shown in the video of the Ray's LENZ free generator. 
> What I will propose is very simple application of DC motor principles
> as read from the cited references. First you make your LENZ free 
> motor which is in reality a LINEAR MOTOR (Solenoid) which will give
> the necessary stroke length to drive the LINEAR generator (Coil
> oscillating within the drag free, LENZ free area of the Neo
> magnets).   Stroke of the solenoid is controlled by Hall sensor and
> IGBT drive switch to give an excursion rate (stroke) at a frequency of
> 60 HZ. By using a DC pulse  to drive the solenoid coil it is tricked
> into being in LOCKED ROTOR condition, thus no LENZ effect.  Has the
> light come on yet??   We know that Ray's generator puts out a sine
> wave output (AC) with no LENZ drag.  Following the DC motor principles
> as applied to the solenoid driver, you have a motor that is LENZ free
> also.  The combo should give an Over-unity output. Now the tricky
> part!  We know as Ole will agree in that when you switch the solenoid
> power to off state as magnetic flux is building toward saturation
> there will be a huge voltage spike (Neutral Spike) which we have to
> capture and not send to ground as ordinary practice in solid state
> switch design (snubber diodes)  The capture of the SPIKE energy (HV)
> which occurs naturally will be the over-unity factor here! 
> Interesting concept!  Think about it!  Norm    Mick! (accumulator HV
> caps)!
>
> On 11/16/2018 6:23 AM, Mick [email protected] [EVGRAY] wrote:
>>  
>>
>> Ole,
>>
>> I have had caps charge much faster in an LC tank than otherwise, but
>> it could also have to do with noise in the core material as I was no
>> using an air inductor.
>>
>>
>> On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
>>>  
>>>
>>> Hi Mick,
>>>
>>> "If a reactive LC tank capacitor is then disconnected from the
>>> reactive source then discharged to a resistive load then reconnected
>>> energized back to the standing wave modality recharged disconnected
>>> discharged etc.  If the reactive energy is harvested in this manner
>>> are you claiming the same losses will occur as power factor
>>> correcting the reactive back into real power?"
>>>
>>> Yes that's correct.
>>>
>>> Common power factor correction in AC is for eliminating the reactive
>>> power that doesn't do any work but just heats the wires between the
>>> power plant and the reactive load. This is expensive for the owners
>>> of the power transmission lines and thus should be avoided. First
>>> storing the energy in a capacitor (or inductor or battery) and then
>>> dumping it to an active load will still make the power go in just
>>> one direction even though it happens in pulses. The energy is then
>>> moving from the source to the load. Reactive power has the energy
>>> moving to and from the load and power source. The power moving
>>> between the capacitor and inductor in an LC-tank is pure reactive
>>> except for the loss because of the parasitic resistance in the
>>> components and wires.
>>>
>>> Regards
>>> Ole
>>>
>>>
>>> ---In [email protected], <mkjekyll@...> wrote :
>>>
>>> Ole,
>>>
>>> Disregarding the issue at hand with the patent terminology and not
>>> concerning ourselves with the patent just a very high Q tank.
>>>
>>> If a reactive LC tank capacitor is then disconnected from the
>>> reactive source then discharged to a resistive load then reconnected
>>> energized back to the standing wave modality recharged disconnected
>>> discharged etc.  If the reactive energy is harvested in this manner
>>> are you claiming the same losses will occur as power factor
>>> correcting the reactive back into real power?
>>>
>>>
>>>
>>> On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...> [EVGRAY] wrote
>>>
>>>>      
>>>>
>>>>     I have only read to the following paragraph cited below. I
>>>>     wonder if the applicant knows about what he is writing.
>>>>
>>>>     Citing paragraph 106 of the patent application
>>>>     (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>>     "[0106] There is voltage across the inductor connected in
>>>>     series to the capacitor and there is voltage across the
>>>>     inductor connected in parallel to the capacitor. Since
>>>>     Power=voltage×current, a single power input produces two
>>>>     branches of electromagnetic power output, increasing the power
>>>>     output. In the alternative, the present disclosure may have one
>>>>     electromagnetic power output with less energy input."
>>>>
>>>>
>>>>
>>>>     It isn't as simple as this. If using an oscilloscope for
>>>>     measuring the current and voltage it will show some phase
>>>>     displacement between the current and voltage which means
>>>>     reactive power. Look at the following small videos to see how
>>>>     one can be misled if not knowing how the phase between the
>>>>     current and voltage is: Only the the resistive part consumes
>>>>     (transforms) energy like R in figure 8.
>>>>
>>>>     0:42
>>>>     <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>
>>>>           Overunity Device Cop 2,5 ? explanation part 3.
>>>>           <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>     9.5K views5 years ago
>>>>     1:01
>>>>     <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>
>>>>           Overunity Device Cop 2,5 ? explanation part 2.
>>>>           <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>     10K views5 years ago
>>>>     1:00
>>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>
>>>>           Overunity Device Cop 2,5 ? part 1. but,
>>>>           <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>     8K views5 years ago
>>>>
>>>>     The numbers without the phase shift looks like overunity which
>>>>     isn't the case when taking into account the phase shift. Only
>>>>     real power is useful in doing work. Reactive power doesn't do
>>>>     work except for the small active part heating the the wires and
>>>>     other components because of their parasitic resistance. This
>>>>     part caused by current doing work against the resistance is
>>>>     active power and not actually reactive power. This is why the
>>>>     power distributing companies may charge costumers for having
>>>>     high reactive power going through their cables which heats the
>>>>     power lines without transferring active power to their
>>>>     costumers. It's just pure loss because the wires have
>>>>     resistance. Resistance converts electric power into heat.
>>>>
>>>>     Just looked at the figures and found the description to figure 46:
>>>>     "[0149]FIG. 46 illustrates an embodiment of the present
>>>>     disclosure that conserves light bulb energy. In a test
>>>>     conducted, on Nov. 16, 1998, a light bulb was installed
>>>>     according to the schematic disclosed in FIG. 46 and is still
>>>>     running seven years later.
>>>>
>>>>     [0150]Since Apparent Power (VA)=Current (A)×Voltage (V), the
>>>>     calculations below illustrate energy conservation for a 60 W
>>>>     light bulb. The voltage applied at the power input is 115 V.
>>>>     The apparent power for the Power Input Line (Line PIN) is
>>>>     measured at 126.5 VA. The apparent power measured for the shed
>>>>     motor fan is 126.5 VA and the apparent power measured for the
>>>>     light bulb is 65 VA. Therefore, 126 VA is measured at the input
>>>>     and a total of 191.5 VA is measured at the output, indicating
>>>>     an approximately 1.5 gain. Calculations are also shown for the
>>>>     energy savings for a 75W Bulb."
>>>>
>>>>     It is the apparent power that is increased. The apparent power
>>>>     is the vector sum of the real power and the reactive power
>>>>     which makes it always greater than or equal to the real (or
>>>>     active or true) power.
>>>>
>>>>
>>>>     Source with description at:
>>>>     https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>>
>>>>     Regards
>>>>     Ole
>>>
>>
>

Hi Mick,

"If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?"

Yes that's correct.

Common power factor correction in AC is for eliminating the reactive power that doesn't do any work but just heats the wires between the power plant and the reactive load. This is expensive for the owners of the power transmission lines and thus should be avoided. First storing the energy in a capacitor (or inductor or battery) and then dumping it to an active load will still make the power go in just one direction even though it happens in pulses. The energy is then moving from the source to the load. Reactive power has the energy moving to and from the load and power source. The power moving between the capacitor and inductor in an LC-tank is pure reactive except for the loss because of the parasitic resistance in the components and wires.

Regards
Ole


---In [email protected], <mkjekyll@...> wrote :

 Ole,
 Disregarding the issue at hand with the patent terminology and not concerning ourselves with the patent just a very high Q tank.
 
 If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?
 
 
 
 
 On 11/15/2018 5:36 PM, onielsen@... mailto:onielsen@... [EVGRAY] wrote
 
   I have only read to the following paragraph cited below. I wonder if the applicant knows about what he is writing.
 
 Citing paragraph 106 of the patent application (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
 "[0106] There is voltage across the inductor connected in series to the capacitor and there is voltage across the inductor connected in parallel to the capacitor. Since Power=voltage×current, a single power input produces two branches of electromagnetic power output, increasing the power output. In the alternative, the present disclosure may have one electromagnetic power output with less energy input."
 
 
 
 It isn't as simple as this. If using an oscilloscope for measuring the current and voltage it will show some phase displacement between the current and voltage which means reactive power. Look at the following small videos to see how one can be misled if not knowing how the phase between the current and voltage is: Only the the resistive part consumes (transforms) energy like R in figure 8.
 
 
 0:42 
 Overunity Device Cop 2,5 ? explanation part 3. 9.5K views5 years ago
 
 
 
 
 
 1:01 
 Overunity Device Cop 2,5 ? explanation part 2. 10K views5 years ago
 
 
 
 
 
 1:00 
 
 https://www.youtube.com/watch?v=P_E0ck3v40Y Overunity Device Cop 2,5 ? part 1. but, 8K views5 years ago
 
 
 
 
 The numbers without the phase shift looks like overunity which isn't the case when taking into account the phase shift. Only real power is useful in doing work. Reactive power doesn't do work except for the small active part heating the the wires and other components because of their parasitic resistance. This part caused by current doing work against the resistance is active power and not actually reactive power. This is why the power distributing companies may charge costumers for having high reactive power going through their cables which heats the power lines without transferring active power to their costumers. It's just pure loss because the wires have resistance. Resistance converts electric power into heat.
 
 Just looked at the figures and found the description to figure 46:
 "[0149] FIG. 46 illustrates an embodiment of the present disclosure that conserves light bulb energy. In a test conducted, on Nov. 16, 1998, a light bulb was installed according to the schematic disclosed in FIG. 46 and is still running seven years later.
 
 [0150] Since Apparent Power (VA)=Current (A)×Voltage (V), the calculations below illustrate energy conservation for a 60 W light bulb. The voltage applied at the power input is 115 V. The apparent power for the Power Input Line (Line PIN) is measured at 126.5 VA. The apparent power measured for the shed motor fan is 126.5 VA and the apparent power measured for the light bulb is 65 VA. Therefore, 126 VA is measured at the input and a total of 191.5 VA is measured at the output, indicating an approximately 1.5 gain. Calculations are also shown for the energy savings for a 75W Bulb."
 
 It is the apparent power that is increased. The apparent power is the vector sum of the real power and the reactive power which makes it always greater than or equal to the real (or active or true) power.
 
 
 Source with description at: https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/ https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
 
 Regards
 Ole

Ole,

So if the cap is disconnected at the even multiple harmonic of the
resonant root frequency synchronized at the proper 1/2 or 1/4 cycle it
is no longer cancelled but carries a charge correct?

On 11/16/2018 9:06 AM, [email protected] [EVGRAY] wrote:
>  
>
> Hi Mick,
>
> At resonance (in LC-tank) the capacitive impedance (imaginary part)
> cancels the inductive impedance (imaginary part) leaving only the
> resistance of the LC-tank circuit. The reactance of a capacitor is
> negative while the reactance of an inductor is positive. At resonance
> they are equal in magnitude but of opposite sign which cancel them out.
>
> LC-tank: https://wiki2.org/en/LC_circuit
> Reactance: https://wiki2.org/en/Electrical_reactance
>
> Regards
> Ole
>
>
> ---In [email protected], <mkjekyll@...> wrote :
>
> Ole,
>
> I have had caps charge much faster in an LC tank than otherwise, but
> it could also have to do with noise in the core material as I was no
> using an air inductor.
>
>
> On 11/16/2018 1:19 AM, onielsen@... <mailto:onielsen@...> [EVGRAY] wrote:
>
>>      
>>
>>     Hi Mick,
>>
>>     "If a reactive LC tank capacitor is then disconnected from the
>>     reactive source then discharged to a resistive load then
>>     reconnected energized back to the standing wave modality
>>     recharged disconnected discharged etc.  If the reactive energy is
>>     harvested in this manner are you claiming the same losses will
>>     occur as power factor correcting the reactive back into real power?"
>>
>>     Yes that's correct.
>>
>>     Common power factor correction in AC is for eliminating the
>>     reactive power that doesn't do any work but just heats the wires
>>     between the power plant and the reactive load. This is expensive
>>     for the owners of the power transmission lines and thus should be
>>     avoided. First storing the energy in a capacitor (or inductor or
>>     battery) and then dumping it to an active load will still make
>>     the power go in just one direction even though it happens in
>>     pulses. The energy is then moving from the source to the load.
>>     Reactive power has the energy moving to and from the load and
>>     power source. The power moving between the capacitor and inductor
>>     in an LC-tank is pure reactive except for the loss because of the
>>     parasitic resistance in the components and wires.
>>
>>     Regards
>>     Ole
>>
>>
>>     ---In [email protected] <mailto:[email protected]>,
>>     <mkjekyll@...> <mailto:mkjekyll@...> wrote :
>>
>>     Ole,
>>
>>     Disregarding the issue at hand with the patent terminology and
>>     not concerning ourselves with the patent just a very high Q tank.
>>
>>     If a reactive LC tank capacitor is then disconnected from the
>>     reactive source then discharged to a resistive load then
>>     reconnected energized back to the standing wave modality
>>     recharged disconnected discharged etc.  If the reactive energy is
>>     harvested in this manner are you claiming the same losses will
>>     occur as power factor correcting the reactive back into real power?
>>
>>
>>
>>     On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...>
>>     [EVGRAY] wrote
>>
>>>          
>>>
>>>         I have only read to the following paragraph cited below. I
>>>         wonder if the applicant knows about what he is writing.
>>>
>>>         Citing paragraph 106 of the patent application
>>>         (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>         "[0106] There is voltage across the inductor connected in
>>>         series to the capacitor and there is voltage across the
>>>         inductor connected in parallel to the capacitor. Since
>>>         Power=voltage×current, a single power input produces two
>>>         branches of electromagnetic power output, increasing the
>>>         power output. In the alternative, the present disclosure may
>>>         have one electromagnetic power output with less energy input."
>>>
>>>
>>>
>>>         It isn't as simple as this. If using an oscilloscope for
>>>         measuring the current and voltage it will show some phase
>>>         displacement between the current and voltage which means
>>>         reactive power. Look at the following small videos to see
>>>         how one can be misled if not knowing how the phase between
>>>         the current and voltage is: Only the the resistive part
>>>         consumes (transforms) energy like R in figure 8.
>>>
>>>         0:42
>>>         <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>
>>>
>>>               Overunity Device Cop 2,5 ? explanation part 3.
>>>               <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>
>>>         9.5K views5 years ago
>>>         1:01
>>>         <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>
>>>
>>>               Overunity Device Cop 2,5 ? explanation part 2.
>>>               <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>
>>>         10K views5 years ago
>>>         1:00
>>>         <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>         <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>
>>>
>>>               Overunity Device Cop 2,5 ? part 1. but,
>>>               <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>
>>>         8K views5 years ago
>>>
>>>         The numbers without the phase shift looks like overunity
>>>         which isn't the case when taking into account the phase
>>>         shift. Only real power is useful in doing work. Reactive
>>>         power doesn't do work except for the small active part
>>>         heating the the wires and other components because of their
>>>         parasitic resistance. This part caused by current doing work
>>>         against the resistance is active power and not actually
>>>         reactive power. This is why the power distributing companies
>>>         may charge costumers for having high reactive power going
>>>         through their cables which heats the power lines without
>>>         transferring active power to their costumers. It's just pure
>>>         loss because the wires have resistance. Resistance converts
>>>         electric power into heat.
>>>
>>>         Just looked at the figures and found the description to
>>>         figure 46:
>>>         "[0149]FIG. 46 illustrates an embodiment of the present
>>>         disclosure that conserves light bulb energy. In a test
>>>         conducted, on Nov. 16, 1998, a light bulb was installed
>>>         according to the schematic disclosed in FIG. 46 and is still
>>>         running seven years later.
>>>
>>>         [0150]Since Apparent Power (VA)=Current (A)×Voltage (V), the
>>>         calculations below illustrate energy conservation for a 60 W
>>>         light bulb. The voltage applied at the power input is 115 V.
>>>         The apparent power for the Power Input Line (Line PIN) is
>>>         measured at 126.5 VA. The apparent power measured for the
>>>         shed motor fan is 126.5 VA and the apparent power measured
>>>         for the light bulb is 65 VA. Therefore, 126 VA is measured
>>>         at the input and a total of 191.5 VA is measured at the
>>>         output, indicating an approximately 1.5 gain. Calculations
>>>         are also shown for the energy savings for a 75W Bulb."
>>>
>>>         It is the apparent power that is increased. The apparent
>>>         power is the vector sum of the real power and the reactive
>>>         power which makes it always greater than or equal to the
>>>         real (or active or true) power.
>>>
>>>
>>>         Source with description at:
>>>         https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>
>>>
>>>         (Message over 64 KB, truncated)
>>
>

Some additional factors that have to be considered such as resonance 
both mechanical and electrical. Mechanical is same as in a pendulum 
action where there is a natural frequency to target based on weight of 
coil and driving mechanism and gravity. (pendulum freq =60 HZ)  The 
electrical will be accomplished via inductance of coil with proper 
capacitive element to achieve the Q factor at operational resonance.

On 11/16/2018 7:55 AM, Norman Wootan wrote:
>
> Mick, Ole, Kone etal!  I have been thinking a lot about my Locked 
> Rotor experiments and did a lot of reading to come up with a fool 
> proof Lenz free motor / generator combination which is so easy to 
> build and proof test! First of all you should read what we know as 
> facts! See the following articles:
>
> https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
>
> http://www.machineryspaces.com/direct-current-motors.html
>
> https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
>
> https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
>
> https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
>
> https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
>
> Kone loves to play with the very powerful Neos as found at K&G 
> Magnetics and shown in the video of the Ray's LENZ free generator.  
> What I will propose is very simple application of DC motor principles 
> as read from the cited references. First you make your LENZ free  
> motor which is in reality a LINEAR MOTOR (Solenoid) which will give 
> the necessary stroke length to drive the LINEAR generator (Coil 
> oscillating within the drag free, LENZ free area of the Neo 
> magnets).   Stroke of the solenoid is controlled by Hall sensor and 
> IGBT drive switch to give an excursion rate (stroke) at a frequency of 
> 60 HZ. By using a DC pulse  to drive the solenoid coil it is tricked 
> into being in LOCKED ROTOR condition, thus no LENZ effect.  Has the 
> light come on yet??   We know that Ray's generator puts out a sine 
> wave output (AC) with no LENZ drag.  Following the DC motor principles 
> as applied to the solenoid driver, you have a motor that is LENZ free 
> also.  The combo should give an Over-unity output. Now the tricky 
> part!  We know as Ole will agree in that when you switch the solenoid 
> power to off state as magnetic flux is building toward saturation 
> there will be a huge voltage spike (Neutral Spike) which we have to 
> capture and not send to ground as ordinary practice in solid state 
> switch design (snubber diodes)  The capture of the SPIKE energy (HV) 
> which occurs naturally will be the over-unity factor here!  
> Interesting concept!  Think about it!  Norm    Mick! (accumulator HV 
> caps)!
>
> On 11/16/2018 6:23 AM, Mick [email protected] [EVGRAY] wrote:
>>
>> Ole,
>>
>> I have had caps charge much faster in an LC tank than otherwise, but 
>> it could also have to do with noise in the core material as I was no 
>> using an air inductor.
>>
>>
>> On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
>>>
>>> Hi Mick,
>>>
>>> "If a reactive LC tank capacitor is then disconnected from the 
>>> reactive source then discharged to a resistive load then reconnected 
>>> energized back to the standing wave modality recharged disconnected 
>>> discharged etc. If the reactive energy is harvested in this manner 
>>> are you claiming the same losses will occur as power factor 
>>> correcting the reactive back into real power?"
>>>
>>> Yes that's correct.
>>>
>>> Common power factor correction in AC is for eliminating the reactive 
>>> power that doesn't do any work but just heats the wires between the 
>>> power plant and the reactive load. This is expensive for the owners 
>>> of the power transmission lines and thus should be avoided. First 
>>> storing the energy in a capacitor (or inductor or battery) and then 
>>> dumping it to an active load will still make the power go in just 
>>> one direction even though it happens in pulses. The energy is then 
>>> moving from the source to the load. Reactive power has the energy 
>>> moving to and from the load and power source. The power moving 
>>> between the capacitor and inductor in an LC-tank is pure reactive 
>>> except for the loss because of the parasitic resistance in the 
>>> components and wires.
>>>
>>> Regards
>>> Ole
>>>
>>>
>>> ---In [email protected], <mkjekyll@...> wrote :
>>>
>>> Ole,
>>>
>>> Disregarding the issue at hand with the patent terminology and not 
>>> concerning ourselves with the patent just a very high Q tank.
>>>
>>> If a reactive LC tank capacitor is then disconnected from the 
>>> reactive source then discharged to a resistive load then reconnected 
>>> energized back to the standing wave modality recharged disconnected 
>>> discharged etc.  If the reactive energy is harvested in this manner 
>>> are you claiming the same losses will occur as power factor 
>>> correcting the reactive back into real power?
>>>
>>>
>>>
>>> On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...> [EVGRAY] wrote
>>>
>>>>     I have only read to the following paragraph cited below. I
>>>>     wonder if the applicant knows about what he is writing.
>>>>
>>>>     Citing paragraph 106 of the patent application
>>>>     (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>>     "[0106] There is voltage across the inductor connected in
>>>>     series to the capacitor and there is voltage across the
>>>>     inductor connected in parallel to the capacitor. Since
>>>>     Power=voltage×current, a single power input produces two
>>>>     branches of electromagnetic power output, increasing the power
>>>>     output. In the alternative, the present disclosure may have one
>>>>     electromagnetic power output with less energy input."
>>>>
>>>>
>>>>
>>>>     It isn't as simple as this. If using an oscilloscope for
>>>>     measuring the current and voltage it will show some phase
>>>>     displacement between the current and voltage which means
>>>>     reactive power. Look at the following small videos to see how
>>>>     one can be misled if not knowing how the phase between the
>>>>     current and voltage is: Only the the resistive part consumes
>>>>     (transforms) energy like R in figure 8.
>>>>
>>>>     0:42
>>>>     <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>
>>>>           Overunity Device Cop 2,5 ? explanation part 3.
>>>>           <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>     9.5K views5 years ago
>>>>     1:01
>>>>     <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>
>>>>           Overunity Device Cop 2,5 ? explanation part 2.
>>>>           <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>     10K views5 years ago
>>>>     1:00
>>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>
>>>>           Overunity Device Cop 2,5 ? part 1. but,
>>>>           <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>     8K views5 years ago
>>>>
>>>>     The numbers without the phase shift looks like overunity which
>>>>     isn't the case when taking into account the phase shift. Only
>>>>     real power is useful in doing work. Reactive power doesn't do
>>>>     work except for the small active part heating the the wires and
>>>>     other components because of their parasitic resistance. This
>>>>     part caused by current doing work against the resistance is
>>>>     active power and not actually reactive power. This is why the
>>>>     power distributing companies may charge costumers for having
>>>>     high reactive power going through their cables which heats the
>>>>     power lines without transferring active power to their
>>>>     costumers. It's just pure loss because the wires have
>>>>     resistance. Resistance converts electric power into heat.
>>>>
>>>>     Just looked at the figures and found the description to figure 46:
>>>>     "[0149]FIG. 46 illustrates an embodiment of the present
>>>>     disclosure that conserves light bulb energy. In a test
>>>>     conducted, on Nov. 16, 1998, a light bulb was installed
>>>>     according to the schematic disclosed in FIG. 46 and is still
>>>>     running seven years later.
>>>>
>>>>     [0150]Since Apparent Power (VA)=Current (A)×Voltage (V), the
>>>>     calculations below illustrate energy conservation for a 60 W
>>>>     light bulb. The voltage applied at the power input is 115 V.
>>>>     The apparent power for the Power Input Line (Line PIN) is
>>>>     measured at 126.5 VA. The apparent power measured for the shed
>>>>     motor fan is 126.5 VA and the apparent power measured for the
>>>>     light bulb is 65 VA. Therefore, 126 VA is measured at the input
>>>>     and a total of 191.5 VA is measured at the output, indicating
>>>>     an approximately 1.5 gain. Calculations are also shown for the
>>>>     energy savings for a 75W Bulb."
>>>>
>>>>     It is the apparent power that is increased. The apparent power
>>>>     is the vector sum of the real power and the reactive power
>>>>     which makes it always greater than or equal to the real (or
>>>>     active or true) power.
>>>>
>>>>
>>>>     Source with description at:
>>>>     https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>>
>>>>     Regards
>>>>     Ole
>>>
>>
>>

Thanks! Warren for giving this some serious thought.

On 11/16/2018 9:50 AM, Warren Keillor [email protected] 
[EVGRAY] wrote:
>
> Hi Norm
>
> I have collected several reciprocal set ups that can utilize solenoid 
> drives, ever since I saw those amazing coil leaps, from our friend in 
> Indonesia.
> One is a water pump, with ball bearings and sump meant for a cottage 
> supply well. The cylinder block is separate, and can easily be 
> replaced by a good sized solenoid,
> that can easily be home custom made. Another is an interesting cast 
> iron treadle, meant in Victorian times to power " power" tools.
> It has the construction and simplicity of a piece of lab equipment, 
> suitable for straight forward video communication, as an educational tool.
> Again, the replacement of the foot pedal with a solenoid piston, is 
> very simple, and graphically instructive, for conceptual communication.
> Machinery is easy for me
> Coils are easy too.
> The tough issue is keeping the signals simple, and straight forward.
> I figure if I can get it to work, we all should be able to do this.
> I now must get to a computer, to open your links, and perhaps print them.
> Cheers Warren
> Sent from Yahoo Mail on Android 
> <https://go.onelink.me/107872968?pid=InProduct&c=Global_Internal_YGrowth_AndroidEmailSig__AndroidUsers&af_wl=ym&af_sub1=Internal&af_sub2=Global_YGrowth&af_sub3=EmailSignature>
>
>     On Fri, 16 Nov 2018 at 9:13 AM, Norman Wootan [email protected] [EVGRAY]
>     <[email protected]> wrote:
>
>     Mick, Ole, Kone etal!  I have been thinking a lot about my Locked
>     Rotor experiments and did a lot of reading to come up with a fool
>     proof Lenz free motor / generator combination which is so easy to
>     build and proof test! First of all you should read what we know as
>     facts! See the following articles:
>
>     https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
>
>     http://www.machineryspaces.com/direct-current-motors.html
>
>     https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
>
>     https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
>
>     https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
>
>     https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
>
>     Kone loves to play with the very powerful Neos as found at K&G
>     Magnetics and shown in the video of the Ray's LENZ free
>     generator.  What I will propose is very simple application of DC
>     motor principles as read from the cited references. First you make
>     your LENZ free  motor which is in reality a LINEAR MOTOR
>     (Solenoid) which will give the necessary stroke length to drive
>     the LINEAR generator (Coil oscillating within the drag free, LENZ
>     free area of the Neo magnets).   Stroke of the solenoid is
>     controlled by Hall sensor and IGBT drive switch to give an
>     excursion rate (stroke) at a frequency of 60 HZ. By using a DC
>     pulse  to drive the solenoid coil it is tricked into being in
>     LOCKED ROTOR condition, thus no LENZ effect.  Has the light come
>     on yet??   We know that Ray's generator puts out a sine wave
>     output (AC) with no LENZ drag.  Following the DC motor principles
>     as applied to the solenoid driver, you have a motor that is LENZ
>     free also.  The combo should give an Over-unity output. Now the
>     tricky part! We know as Ole will agree in that when you switch the
>     solenoid power to off state as magnetic flux is building toward
>     saturation there will be a huge voltage spike (Neutral Spike)
>     which we have to capture and not send to ground as ordinary
>     practice in solid state switch design (snubber diodes)  The
>     capture of the SPIKE energy (HV) which occurs naturally will be
>     the over-unity factor here!  Interesting concept!  Think about
>     it!  Norm    Mick! (accumulator HV caps)!
>
>     On 11/16/2018 6:23 AM, Mick [email protected]
>     <mailto:[email protected]> [EVGRAY] wrote:
>>
>>     Ole,
>>
>>     I have had caps charge much faster in an LC tank than otherwise,
>>     but it could also have to do with noise in the core material as I
>>     was no using an air inductor.
>>
>>
>>     On 11/16/2018 1:19 AM, [email protected]
>>     <mailto:[email protected]> [EVGRAY] wrote:
>>>
>>>     Hi Mick,
>>>
>>>     "If a reactive LC tank capacitor is then disconnected from the
>>>     reactive source then discharged to a resistive load then
>>>     reconnected energized back to the standing wave modality
>>>     recharged disconnected discharged etc.  If the reactive energy
>>>     is harvested in this manner are you claiming the same losses
>>>     will occur as power factor correcting the reactive back into
>>>     real power?"
>>>
>>>     Yes that's correct.
>>>
>>>     Common power factor correction in AC is for eliminating the
>>>     reactive power that doesn't do any work but just heats the wires
>>>     between the power plant and the reactive load. This is expensive
>>>     for the owners of the power transmission lines and thus should
>>>     be avoided. First storing the energy in a capacitor (or inductor
>>>     or battery) and then dumping it to an active load will still
>>>     make the power go in just one direction even though it happens
>>>     in pulses. The energy is then moving from the source to the
>>>     load. Reactive power has the energy moving to and from the load
>>>     and power source. The power moving between the capacitor and
>>>     inductor in an LC-tank is pure reactive except for the loss
>>>     because of the parasitic resistance in the components and wires.
>>>
>>>     Regards
>>>     Ole
>>>
>>>
>>>     ---In [email protected] <mailto:[email protected]>,
>>>     <mkjekyll@...> <mailto:mkjekyll@...> wrote :
>>>
>>>     Ole,
>>>
>>>     Disregarding the issue at hand with the patent terminology and
>>>     not concerning ourselves with the patent just a very high Q tank.
>>>
>>>     If a reactive LC tank capacitor is then disconnected from the
>>>     reactive source then discharged to a resistive load then
>>>     reconnected energized back to the standing wave modality
>>>     recharged disconnected discharged etc. If the reactive energy is
>>>     harvested in this manner are you claiming the same losses will
>>>     occur as power factor correcting the reactive back into real power?
>>>
>>>
>>>
>>>     On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...>
>>>     [EVGRAY] wrote
>>>
>>>>         I have only read to the following paragraph cited below. I
>>>>         wonder if the applicant knows about what he is writing.
>>>>
>>>>         Citing paragraph 106 of the patent application
>>>>         (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>>         "[0106] There is voltage across the inductor connected in
>>>>         series to the capacitor and there is voltage across the
>>>>         inductor connected in parallel to the capacitor. Since
>>>>         Power=voltage×current, a single power input produces two
>>>>         branches of electromagnetic power output, increasing the
>>>>         power output. In the alternative, the present disclosure
>>>>         may have one electromagnetic power output with less energy
>>>>         input."
>>>>
>>>>         alt
>>>>
>>>>         It isn't as simple as this. If using an oscilloscope for
>>>>         measuring the current and voltage it will show some phase
>>>>         displacement between the current and voltage which means
>>>>         reactive power. Look at the following small videos to see
>>>>         how one can be misled if not knowing how the phase between
>>>>         the current and voltage is: Only the the resistive part
>>>>         consumes (transforms) energy like R in figure 8.
>>>>
>>>>         alt
>>>>         0:42
>>>>         <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>
>>>>               Overunity Device Cop 2,5 ? explanation part 3.
>>>>               <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>         9.5K views5 years ago
>>>>         alt
>>>>         1:01
>>>>         <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>
>>>>               Overunity Device Cop 2,5 ? explanation part 2.
>>>>               <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>         10K views5 years ago
>>>>         alt
>>>>         1:00
>>>>         <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>         <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>
>>>>               Overunity Device Cop 2,5 ? part 1. but,
>>>>               <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>         8K views5 years ago
>>>>
>>>>         The numbers without the phase shift looks like overunity
>>>>         which isn't the case when taking into account the phase
>>>>         shift. Only real power is useful in doing work. Reactive
>>>>         power doesn't do work except for the small active part
>>>>         heating the the wires and other components because of their
>>>>         parasitic resistance. This part caused by current doing
>>>>         work against the resistance is active power and not
>>>>         actually reactive power. This is why the power distributing
>>>>         companies may charge costumers for having high reactive
>>>>         power going through their cables which heats the power
>>>>         lines without transferring active power to their costumers.
>>>>         It's just pure loss because the wires have resistance.
>>>>         Resistance converts electric power into heat.
>>>>
>>>>         Just looked at the figures and found the description to
>>>>         figure 46:
>>>>         "[0149]FIG. 46 illustrates an embodiment of the present
>>>>         disclosure that conserves light bulb energy. In a test
>>>>         conducted, on Nov. 16, 1998, a light bulb was installed
>>>>         according to the schematic disclosed in FIG. 46 and is
>>>>         still running seven years later.
>>>>
>>>>         [0150]Since Apparent Power (VA)=Current (A)×Voltage (V),
>>>>         the calculations below illustrate energy conservation for a
>>>>         60 W light bulb. The voltage applied at the power input is
>>>>         115 V. The apparent power for the Power Input Line (Line
>>>>         PIN) is measured at 126.5 VA. The apparent power measured
>>>>         for the shed motor fan is 126.5 VA and the apparent power
>>>>         measured for the light bulb is 65 VA. Therefore, 126 VA is
>>>>         measured at the input and a total of 191.5 VA is measured
>>>>         at the output, indicating an approximately 1.5 gain.
>>>>         Calculations are also shown for the energy savings for a
>>>>         75W Bulb."
>>>>
>>>>         It is the apparent power that is increased. The apparent
>>>>         power is the vector sum of the real power and the reactive
>>>>         power which makes it always greater than or equal to the
>>>>         real (or active or true) power.
>>>>
>>>>
>>>>         Source with description at:
>>>>         https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>>
>>>>         Regards
>>>>         Ole
>>>
>>
>

Precisely!

On 11/16/2018 10:24 AM, Mick [email protected] [EVGRAY] wrote:
>
> Norm,
>
> Sounds like a Tesla oscillator powered by DC instead of air!
>
> OK need to read links and think...
>
> On 11/16/2018 5:55 AM, Norman Wootan [email protected] [EVGRAY] wrote:
>>
>> Mick, Ole, Kone etal!  I have been thinking a lot about my Locked 
>> Rotor experiments and did a lot of reading to come up with a fool 
>> proof Lenz free motor / generator combination which is so easy to 
>> build and proof test! First of all you should read what we know as 
>> facts! See the following articles:
>>
>> https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
>>
>> http://www.machineryspaces.com/direct-current-motors.html
>>
>> https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
>>
>> https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
>>
>> https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
>>
>> https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
>>
>> Kone loves to play with the very powerful Neos as found at K&G 
>> Magnetics and shown in the video of the Ray's LENZ free generator.  
>> What I will propose is very simple application of DC motor principles 
>> as read from the cited references. First you make your LENZ free  
>> motor which is in reality a LINEAR MOTOR (Solenoid) which will give 
>> the necessary stroke length to drive the LINEAR generator (Coil 
>> oscillating within the drag free, LENZ free area of the Neo magnets). 
>> Stroke of the solenoid is controlled by Hall sensor and IGBT drive 
>> switch to give an excursion rate (stroke) at a frequency of 60 HZ. By 
>> using a DC pulse to drive the solenoid coil it is tricked into being 
>> in LOCKED ROTOR condition, thus no LENZ effect.  Has the light come 
>> on yet??   We know that Ray's generator puts out a sine wave output 
>> (AC) with no LENZ drag. Following the DC motor principles as applied 
>> to the solenoid driver, you have a motor that is LENZ free also.  The 
>> combo should give an Over-unity output. Now the tricky part!  We know 
>> as Ole will agree in that when you switch the solenoid power to off 
>> state as magnetic flux is building toward saturation there will be a 
>> huge voltage spike (Neutral Spike) which we have to capture and not 
>> send to ground as ordinary practice in solid state switch design 
>> (snubber diodes)  The capture of the SPIKE energy (HV) which occurs 
>> naturally will be the over-unity factor here! Interesting concept!  
>> Think about it!  Norm    Mick! (accumulator HV caps)!
>>
>> On 11/16/2018 6:23 AM, Mick [email protected] [EVGRAY] wrote:
>>>
>>> Ole,
>>>
>>> I have had caps charge much faster in an LC tank than otherwise, but 
>>> it could also have to do with noise in the core material as I was no 
>>> using an air inductor.
>>>
>>>
>>> On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
>>>>
>>>> Hi Mick,
>>>>
>>>> "If a reactive LC tank capacitor is then disconnected from the 
>>>> reactive source then discharged to a resistive load then 
>>>> reconnected energized back to the standing wave modality recharged 
>>>> disconnected discharged etc.  If the reactive energy is harvested 
>>>> in this manner are you claiming the same losses will occur as power 
>>>> factor correcting the reactive back into real power?"
>>>>
>>>> Yes that's correct.
>>>>
>>>> Common power factor correction in AC is for eliminating the 
>>>> reactive power that doesn't do any work but just heats the wires 
>>>> between the power plant and the reactive load. This is expensive 
>>>> for the owners of the power transmission lines and thus should be 
>>>> avoided. First storing the energy in a capacitor (or inductor or 
>>>> battery) and then dumping it to an active load will still make the 
>>>> power go in just one direction even though it happens in pulses. 
>>>> The energy is then moving from the source to the load. Reactive 
>>>> power has the energy moving to and from the load and power source. 
>>>> The power moving between the capacitor and inductor in an LC-tank 
>>>> is pure reactive except for the loss because of the parasitic 
>>>> resistance in the components and wires.
>>>>
>>>> Regards
>>>> Ole
>>>>
>>>>
>>>> ---In [email protected], <mkjekyll@...> wrote :
>>>>
>>>> Ole,
>>>>
>>>> Disregarding the issue at hand with the patent terminology and not 
>>>> concerning ourselves with the patent just a very high Q tank.
>>>>
>>>> If a reactive LC tank capacitor is then disconnected from the 
>>>> reactive source then discharged to a resistive load then 
>>>> reconnected energized back to the standing wave modality recharged 
>>>> disconnected discharged etc.  If the reactive energy is harvested 
>>>> in this manner are you claiming the same losses will occur as power 
>>>> factor correcting the reactive back into real power?
>>>>
>>>>
>>>>
>>>> On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...> [EVGRAY] 
>>>> wrote
>>>>
>>>>>     I have only read to the following paragraph cited below. I
>>>>>     wonder if the applicant knows about what he is writing.
>>>>>
>>>>>     Citing paragraph 106 of the patent application
>>>>>     (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>>>     "[0106] There is voltage across the inductor connected in
>>>>>     series to the capacitor and there is voltage across the
>>>>>     inductor connected in parallel to the capacitor. Since
>>>>>     Power=voltage×current, a single power input produces two
>>>>>     branches of electromagnetic power output, increasing the power
>>>>>     output. In the alternative, the present disclosure may have
>>>>>     one electromagnetic power output with less energy input."
>>>>>
>>>>>
>>>>>
>>>>>     It isn't as simple as this. If using an oscilloscope for
>>>>>     measuring the current and voltage it will show some phase
>>>>>     displacement between the current and voltage which means
>>>>>     reactive power. Look at the following small videos to see how
>>>>>     one can be misled if not knowing how the phase between the
>>>>>     current and voltage is: Only the the resistive part consumes
>>>>>     (transforms) energy like R in figure 8.
>>>>>
>>>>>     0:42
>>>>>     <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>>
>>>>>
>>>>>           Overunity Device Cop 2,5 ? explanation part 3.
>>>>>           <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>>
>>>>>     9.5K views5 years ago
>>>>>     1:01
>>>>>     <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>>
>>>>>
>>>>>           Overunity Device Cop 2,5 ? explanation part 2.
>>>>>           <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>>
>>>>>     10K views5 years ago
>>>>>     1:00
>>>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>>     <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>>
>>>>>
>>>>>           Overunity Device Cop 2,5 ? part 1. but,
>>>>>           <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>>
>>>>>     8K views5 years ago
>>>>>
>>>>>     The numbers without the phase shift looks like overunity which
>>>>>     isn't the case when taking into account the phase shift. Only
>>>>>     real power is useful in doing work. Reactive power doesn't do
>>>>>     work except for the small active part heating the the wires
>>>>>     and other components because of their parasitic resistance.
>>>>>     This part caused by current doing work against the resistance
>>>>>     is active power and not actually reactive power. This is why
>>>>>     the power distributing companies may charge costumers for
>>>>>     having high reactive power going through their cables which
>>>>>     heats the power lines without transferring active power to
>>>>>     their costumers. It's just pure loss because the wires have
>>>>>     resistance. Resistance converts electric power into heat.
>>>>>
>>>>>     Just looked at the figures and found the description to figure 46:
>>>>>     "[0149]FIG. 46 illustrates an embodiment of the present
>>>>>     disclosure that conserves light bulb energy. In a test
>>>>>     conducted, on Nov. 16, 1998, a light bulb was installed
>>>>>     according to the schematic disclosed in FIG. 46 and is still
>>>>>     running seven years later.
>>>>>
>>>>>     [0150]Since Apparent Power (VA)=Current (A)×Voltage (V), the
>>>>>     calculations below illustrate energy conservation for a 60 W
>>>>>     light bulb. The voltage applied at the power input is 115 V.
>>>>>     The apparent power for the Power Input Line (Line PIN) is
>>>>>     measured at 126.5 VA. The apparent power measured for the shed
>>>>>     motor fan is 126.5 VA and the apparent power measured for the
>>>>>     light bulb is 65 VA. Therefore, 126 VA is measured at the
>>>>>     input and a total of 191.5 VA is measured at the output,
>>>>>     indicating an approximately 1.5 gain. Calculations are also
>>>>>     shown for the energy savings for a 75W Bulb."
>>>>>
>>>>>     It is the apparent power that is increased. The apparent power
>>>>>     is the vector sum of the real power and the reactive power
>>>>>     which makes it always greater than or equal to the real (or
>>>>>     active or true) power.
>>>>>
>>>>>
>>>>>     Source with description at:
>>>>>     https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>>>
>>>>>     Regards
>>>>>     Ole
>>>>
>>>
>

Warren, Iron,  Further thought on this as follows!    The solenoid 
linear motor can be operated just the same as the old Outboard Marine 
Magnetos that I studied to such detail.  What made them so efficient was 
the three pole coil stator which received a forward going current in 
primary windings , magnets passing 1st and 2nd pole pieces before top 
dead center which charged up the condenser when current reached peak. 
When breaker points opened the rotating magnets were passing the 2nd and 
3rd pole pieces inducing a reverse polarity current in the primary 
windings and the discharge current from the condenser was in phase which 
accelerated the magnetic flux reversal. On a scope the primary current 
represented an instantaneous straight down line (nano second response). 
This was accomplished due to the fact that the .026mfd condenser was a 
perfect L_C match with the coil impedance. (Ultra high Q) . It is 
important to incorporate this magneto electric effect into the switching 
design of the solenoid linear motor.  See, there is a L-C high Q 
relationship here.  I just threw out the 60 HZ time base but for design 
simplicity, any switching frequency can be selected.  Just as the Tesla 
mechanical oscillators worked at a relative low frequency! Just as 
pointed out, we are making a Tesla Oscillator which is driven by DC . 
Thoughts???

On 11/16/2018 9:58 AM, Warren Keillor [email protected] 
[EVGRAY] wrote:
>
> Norm
>
> The mechanical  contraptions that I have out lined, should be very 
> suitable for applying mechanical switches, timed to the stroke.
> I like the fact nothing can be hidden to view, happening in a mysterious
> "Black box"as even discrete components in a circuit can be confusing.
> It would be so great to hear your further thoughts on this subject.
> Cheers Warren
> Sent from Yahoo Mail on Android 
> <https://go.onelink.me/107872968?pid=InProduct&c=Global_Internal_YGrowth_AndroidEmailSig__AndroidUsers&af_wl=ym&af_sub1=Internal&af_sub2=Global_YGrowth&af_sub3=EmailSignature>
>
>     On Fri, 16 Nov 2018 at 9:13 AM, Norman Wootan [email protected] [EVGRAY]
>     <[email protected]> wrote:
>
>     Mick, Ole, Kone etal!  I have been thinking a lot about my Locked
>     Rotor experiments and did a lot of reading to come up with a fool
>     proof Lenz free motor / generator combination which is so easy to
>     build and proof test! First of all you should read what we know as
>     facts! See the following articles:
>
>     https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
>
>     http://www.machineryspaces.com/direct-current-motors.html
>
>     https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
>
>     https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
>
>     https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
>
>     https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
>
>     Kone loves to play with the very powerful Neos as found at K&G
>     Magnetics and shown in the video of the Ray's LENZ free
>     generator.  What I will propose is very simple application of DC
>     motor principles as read from the cited references. First you make
>     your LENZ free  motor which is in reality a LINEAR MOTOR
>     (Solenoid) which will give the necessary stroke length to drive
>     the LINEAR generator (Coil oscillating within the drag free, LENZ
>     free area of the Neo magnets).   Stroke of the solenoid is
>     controlled by Hall sensor and IGBT drive switch to give an
>     excursion rate (stroke) at a frequency of 60 HZ. By using a DC
>     pulse  to drive the solenoid coil it is tricked into being in
>     LOCKED ROTOR condition, thus no LENZ effect.  Has the light come
>     on yet??   We know that Ray's generator puts out a sine wave
>     output (AC) with no LENZ drag.  Following the DC motor principles
>     as applied to the solenoid driver, you have a motor that is LENZ
>     free also.  The combo should give an Over-unity output. Now the
>     tricky part! We know as Ole will agree in that when you switch the
>     solenoid power to off state as magnetic flux is building toward
>     saturation there will be a huge voltage spike (Neutral Spike)
>     which we have to capture and not send to ground as ordinary
>     practice in solid state switch design (snubber diodes)  The
>     capture of the SPIKE energy (HV) which occurs naturally will be
>     the over-unity factor here!  Interesting concept!  Think about
>     it!  Norm    Mick! (accumulator HV caps)!
>
>     On 11/16/2018 6:23 AM, Mick [email protected]
>     <mailto:[email protected]> [EVGRAY] wrote:
>>
>>     Ole,
>>
>>     I have had caps charge much faster in an LC tank than otherwise,
>>     but it could also have to do with noise in the core material as I
>>     was no using an air inductor.
>>
>>
>>     On 11/16/2018 1:19 AM, [email protected]
>>     <mailto:[email protected]> [EVGRAY] wrote:
>>>
>>>     Hi Mick,
>>>
>>>     "If a reactive LC tank capacitor is then disconnected from the
>>>     reactive source then discharged to a resistive load then
>>>     reconnected energized back to the standing wave modality
>>>     recharged disconnected discharged etc.  If the reactive energy
>>>     is harvested in this manner are you claiming the same losses
>>>     will occur as power factor correcting the reactive back into
>>>     real power?"
>>>
>>>     Yes that's correct.
>>>
>>>     Common power factor correction in AC is for eliminating the
>>>     reactive power that doesn't do any work but just heats the wires
>>>     between the power plant and the reactive load. This is expensive
>>>     for the owners of the power transmission lines and thus should
>>>     be avoided. First storing the energy in a capacitor (or inductor
>>>     or battery) and then dumping it to an active load will still
>>>     make the power go in just one direction even though it happens
>>>     in pulses. The energy is then moving from the source to the
>>>     load. Reactive power has the energy moving to and from the load
>>>     and power source. The power moving between the capacitor and
>>>     inductor in an LC-tank is pure reactive except for the loss
>>>     because of the parasitic resistance in the components and wires.
>>>
>>>     Regards
>>>     Ole
>>>
>>>
>>>     ---In [email protected] <mailto:[email protected]>,
>>>     <mkjekyll@...> <mailto:mkjekyll@...> wrote :
>>>
>>>     Ole,
>>>
>>>     Disregarding the issue at hand with the patent terminology and
>>>     not concerning ourselves with the patent just a very high Q tank.
>>>
>>>     If a reactive LC tank capacitor is then disconnected from the
>>>     reactive source then discharged to a resistive load then
>>>     reconnected energized back to the standing wave modality
>>>     recharged disconnected discharged etc. If the reactive energy is
>>>     harvested in this manner are you claiming the same losses will
>>>     occur as power factor correcting the reactive back into real power?
>>>
>>>
>>>
>>>     On 11/15/2018 5:36 PM, onielsen@... <mailto:onielsen@...>
>>>     [EVGRAY] wrote
>>>
>>>>         I have only read to the following paragraph cited below. I
>>>>         wonder if the applicant knows about what he is writing.
>>>>
>>>>         Citing paragraph 106 of the patent application
>>>>         (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
>>>>         "[0106] There is voltage across the inductor connected in
>>>>         series to the capacitor and there is voltage across the
>>>>         inductor connected in parallel to the capacitor. Since
>>>>         Power=voltage×current, a single power input produces two
>>>>         branches of electromagnetic power output, increasing the
>>>>         power output. In the alternative, the present disclosure
>>>>         may have one electromagnetic power output with less energy
>>>>         input."
>>>>
>>>>         alt
>>>>
>>>>         It isn't as simple as this. If using an oscilloscope for
>>>>         measuring the current and voltage it will show some phase
>>>>         displacement between the current and voltage which means
>>>>         reactive power. Look at the following small videos to see
>>>>         how one can be misled if not knowing how the phase between
>>>>         the current and voltage is: Only the the resistive part
>>>>         consumes (transforms) energy like R in figure 8.
>>>>
>>>>         alt
>>>>         0:42
>>>>         <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>
>>>>               Overunity Device Cop 2,5 ? explanation part 3.
>>>>               <https://www.youtube.com/watch?v=yJEZMCCBV3U>
>>>>
>>>>         9.5K views5 years ago
>>>>         alt
>>>>         1:01
>>>>         <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>
>>>>               Overunity Device Cop 2,5 ? explanation part 2.
>>>>               <https://www.youtube.com/watch?v=Jamj3-2w0eE>
>>>>
>>>>         10K views5 years ago
>>>>         alt
>>>>         1:00
>>>>         <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>         <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>
>>>>               Overunity Device Cop 2,5 ? part 1. but,
>>>>               <https://www.youtube.com/watch?v=P_E0ck3v40Y>
>>>>
>>>>         8K views5 years ago
>>>>
>>>>         The numbers without the phase shift looks like overunity
>>>>         which isn't the case when taking into account the phase
>>>>         shift. Only real power is useful in doing work. Reactive
>>>>         power doesn't do work except for the small active part
>>>>         heating the the wires and other components because of their
>>>>         parasitic resistance. This part caused by current doing
>>>>         work against the resistance is active power and not
>>>>         actually reactive power. This is why the power distributing
>>>>         companies may charge costumers for having high reactive
>>>>         power going through their cables which heats the power
>>>>         lines without transferring active power to their costumers.
>>>>         It's just pure loss because the wires have resistance.
>>>>         Resistance converts electric power into heat.
>>>>
>>>>         Just looked at the figures and found the description to
>>>>         figure 46:
>>>>         "[0149]FIG. 46 illustrates an embodiment of the present
>>>>         disclosure that conserves light bulb energy. In a test
>>>>         conducted, on Nov. 16, 1998, a light bulb was installed
>>>>         according to the schematic disclosed in FIG. 46 and is
>>>>         still running seven years later.
>>>>
>>>>         [0150]Since Apparent Power (VA)=Current (A)×Voltage (V),
>>>>         the calculations below illustrate energy conservation for a
>>>>         60 W light bulb. The voltage applied at the power input is
>>>>         115 V. The apparent power for the Power Input Line (Line
>>>>         PIN) is measured at 126.5 VA. The apparent power measured
>>>>         for the shed motor fan is 126.5 VA and the apparent power
>>>>         measured for the light bulb is 65 VA. Therefore, 126 VA is
>>>>         measured at the input and a total of 191.5 VA is measured
>>>>         at the output, indicating an approximately 1.5 gain.
>>>>         Calculations are also shown for the energy savings for a
>>>>         75W Bulb."
>>>>
>>>>         It is the apparent power that is increased. The apparent
>>>>         power is the vector sum of the real power and the reactive
>>>>         power which makes it always greater than or equal to the
>>>>         real (or active or true) power.
>>>>
>>>>
>>>>         Source with description at:
>>>>         https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
>>>>
>>>>         Regards
>>>>         Ole
>>>
>>
>

Iron, I haven't figured out what he is doing in version two!  By full 
rotation, he seems to violate his no LENZ, no drag concept!

On 11/16/2018 12:11 PM, [email protected] [EVGRAY] wrote:
>
> Norm,
>
>
> What is Ray doing in Version 2, varying the magnetic field?
>
> Is this somewhat similar to Clemente Figuera?
>
> Ron
>

Hi Norman,

Just watched most of this video 'Ray's No Back EMF Generator Design 2' (https://www.youtube.com/watch?v=tRROFwwz5hQ https://www.youtube.com/watch?v=tRROFwwz5hQ).

Ron is talking about a small increase in the input power for an output power bigger than the increase of the input power. This is a wrong way of calculating the efficiency. Motors have different efficiencies depending on load. Thus this tells nothing about what really happens without consulting the datasheet of the motor or measuring the data himself.

Ron also mentions that the magnetic field of the rotor is only north poles. He forgets that magnetic fields are always forming loops. The field goes all the way through the magnet out of it and back into it at the opposite pole. The reason for having a good magnetic conductor with as small as possible air gap in motors and generators is that air is a quite bad conductor of magnetism. If using big air gaps or long magnetic paths the motor will be very big even for small power. Just take a look at early motors before the double T-armature of Werner Siemens: https://www.eti.kit.edu/english/1376.php https://www.eti.kit.edu/english/1376.php. After that motors got more power and the magnetic path was further reduced by I think Nikola Tesla: https://www.eti.kit.edu/english/1390.php https://www.eti.kit.edu/english/1390.php.

Regards
Ole

 

---In [email protected], <nwootan@...> wrote :

 Iron, I haven't figured out what he is doing in version two!  By full rotation, he seems to violate his no LENZ, no drag concept!  

 On 11/16/2018 12:11 PM, iron1of1@... mailto:iron1of1@... [EVGRAY] wrote:

   Norm,
 

 What is Ray doing in Version 2, varying the magnetic field?
 

 Is this somewhat similar to Clemente Figuera?
 

 Ron

Hi NormI have collected several reciprocal set ups that can utilize solenoid drives, ever since I saw those amazing coil leaps, from our friend in Indonesia.One is a water pump, with ball bearings and sump meant for a cottage supply well. The cylinder block is separate, and can easily be replaced by a good sized solenoid,
that can easily be home custom made. Another is an interesting cast iron treadle, meant in Victorian times to power " power" tools.It has the construction and simplicity of a piece of lab equipment, suitable for straight forward video communication, as an educational tool.Again, the replacement of the foot pedal with a solenoid piston, is very simple, and graphically instructive, for conceptual communication.Machinery is easy for meCoils are easy too.The tough issue is keeping the signals simple, and straight forward.I figure if I can get it to work, we all should be able to do this.I now must get to a computer, to open your links, and perhaps print them.Cheers Warren
Sent from Yahoo Mail on Android 
 
  On Fri, 16 Nov 2018 at 9:13 AM, Norman Wootan [email protected] [EVGRAY]<[email protected]> wrote:       
 

Mick, Ole, Kone etal!  I have been thinking a lot about my Locked Rotor experiments and did a lot of reading to come up with a fool proof Lenz free motor / generator combination which is so easy to build and proof test! First of all you should read what we know as facts! See the following articles:
 
https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
 
http://www.machineryspaces.com/direct-current-motors.html
 
https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
 
https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
 
https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
 
https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
 
Kone loves to play with the very powerful Neos as found at K&G Magnetics and shown in the video of the Ray's LENZ free generator.  What I will propose is very simple application of DC motor principles as read from the cited references. First you make your LENZ free  motor which is in reality a LINEAR MOTOR (Solenoid) which will give the necessary stroke length to drive the LINEAR generator (Coil oscillating within the drag free, LENZ free area of the Neo magnets).   Stroke of the solenoid is controlled by Hall sensor and IGBT drive switch to give an excursion rate (stroke) at a frequency of 60 HZ. By using a DC pulse  to drive the solenoid coil it is tricked into being in LOCKED ROTOR condition, thus no LENZ effect.  Has the light come on yet??   We know that Ray's generator puts out a sine wave output (AC) with no LENZ drag.  Following the DC motor principles as applied to the solenoid driver, you have a motor that is LENZ free also.  The combo should give an Over-unity output. Now the tricky part!  We know as Ole will agree in that when you switch the solenoid power to off state as magnetic flux is building toward saturation there will be a huge voltage spike (Neutral Spike) which we have to capture and not send to ground as ordinary practice in solid state switch design (snubber diodes)  The capture of the SPIKE energy (HV) which occurs naturally will be the over-unity factor here!  Interesting concept!  Think about it!  Norm    Mick! (accumulator HV caps)!
 
 On 11/16/2018 6:23 AM, Mick [email protected] [EVGRAY] wrote:
  
    
 
 
Ole,
 
I have had caps charge much faster in an LC tank than otherwise, but it could also have to do with noise in the core material as I was no using an air inductor.
 
 
 On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
  
    
Hi Mick,
 
 "If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?"
 
 Yes that's correct.
 
 Common power factor correction in AC is for eliminating the reactive power that doesn't do any work but just heats the wires between the power plant and the reactive load. This is expensive for the owners of the power transmission lines and thus should be avoided. First storing the energy in a capacitor (or inductor or battery) and then dumping it to an active load will still make the power go in just one direction even though it happens in pulses. The energy is then moving from the source to the load. Reactive power has the energy moving to and from the load and power source. The power moving between the capacitor and inductor in an LC-tank is pure reactive except for the loss because of the parasitic resistance in the components and wires.
 
 Regards
 Ole
 
 
 ---In [email protected], <mkjekyll@...> wrote :
 
 
  
Ole,
 
Disregarding the issue at hand with the patent terminology and not concerning ourselves with the patent just a very high Q tank.
 
 
If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?
 

 
 

 
 On 11/15/2018 5:36 PM, onielsen@... [EVGRAY] wrote
  
 
    
I have only read to the following paragraph cited below. I wonder if the applicant knows about what he is writing.
 
 Citing paragraph 106 of the patent application (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
 "[0106] There is voltage across the inductor connected in series to the capacitor and there is voltage across the inductor connected in parallel to the capacitor. Since Power=voltage×current, a single power input produces two branches of electromagnetic power output, increasing the power output. In the alternative, the present disclosure may have one electromagnetic power output with less energy input."
 
 
 
 It isn't as simple as this. If using an oscilloscope for measuring the current and voltage it will show some phase displacement between the current and voltage which means reactive power. Look at the following small videos to see how one can be misled if not knowing how the phase between the current and voltage is: Only the the resistive part consumes (transforms) energy like R in figure 8.
 
 
     0:42     
Overunity Device Cop 2,5 ? explanation part 3.
   9.5K views5 years ago          1:01     
Overunity Device Cop 2,5 ? explanation part 2.
   10K views5 years ago          1:00      
Overunity Device Cop 2,5 ? part 1. but,
   8K views5 years ago    
 The numbers without the phase shift looks like overunity which isn't the case when taking into account the phase shift. Only real power is useful in doing work. Reactive power doesn't do work except for the small active part heating the the wires and other components because of their parasitic resistance. This part caused by current doing work against the resistance is active power and not actually reactive power. This is why the power distributing companies may charge costumers for having high reactive power going through their cables which heats the power lines without transferring active power to their costumers. It's just pure loss because the wires have resistance. Resistance converts electric power into heat.
 
 Just looked at the figures and found the description to figure 46:
 "[0149] FIG. 46 illustrates an embodiment of the present disclosure that conserves light bulb energy. In a test conducted, on Nov. 16, 1998, a light bulb was installed according to the schematic disclosed in FIG. 46 and is still running seven years later.
 
 [0150] Since Apparent Power (VA)=Current (A)×Voltage (V), the calculations below illustrate energy conservation for a 60 W light bulb. The voltage applied at the power input is 115 V. The apparent power for the Power Input Line (Line PIN) is measured at 126.5 VA. The apparent power measured for the shed motor fan is 126.5 VA and the apparent power measured for the light bulb is 65 VA. Therefore, 126 VA is measured at the input and a total of 191.5 VA is measured at the output, indicating an approximately 1.5 gain. Calculations are also shown for the energy savings for a 75W Bulb."
 
 It is the apparent power that is increased. The apparent power is the vector sum of the real power and the reactive power which makes it always greater than or equal to the real (or active or true) power.
 
 
 Source with description at: https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
 
 Regards
 Ole  
 
   
 
  
  #yiv6016081564 #yiv6016081564 -- #yiv6016081564ygrp-mkp {border:1px solid #d8d8d8;font-family:Arial;margin:10px 0;padding:0 10px;}#yiv6016081564 #yiv6016081564ygrp-mkp hr {border:1px solid #d8d8d8;}#yiv6016081564 #yiv6016081564ygrp-mkp #yiv6016081564hd {color:#628c2a;font-size:85%;font-weight:700;line-height:122%;margin:10px 0;}#yiv6016081564 #yiv6016081564ygrp-mkp #yiv6016081564ads {margin-bottom:10px;}#yiv6016081564 #yiv6016081564ygrp-mkp .yiv6016081564ad {padding:0 0;}#yiv6016081564 #yiv6016081564ygrp-mkp .yiv6016081564ad p {margin:0;}#yiv6016081564 #yiv6016081564ygrp-mkp .yiv6016081564ad a {color:#0000ff;text-decoration:none;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ygrp-lc {font-family:Arial;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ygrp-lc #yiv6016081564hd {margin:10px 0px;font-weight:700;font-size:78%;line-height:122%;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ygrp-lc .yiv6016081564ad {margin-bottom:10px;padding:0 0;}#yiv6016081564 #yiv6016081564actions {font-family:Verdana;font-size:11px;padding:10px 0;}#yiv6016081564 #yiv6016081564activity {background-color:#e0ecee;float:left;font-family:Verdana;font-size:10px;padding:10px;}#yiv6016081564 #yiv6016081564activity span {font-weight:700;}#yiv6016081564 #yiv6016081564activity span:first-child {text-transform:uppercase;}#yiv6016081564 #yiv6016081564activity span a {color:#5085b6;text-decoration:none;}#yiv6016081564 #yiv6016081564activity span span {color:#ff7900;}#yiv6016081564 #yiv6016081564activity span .yiv6016081564underline {text-decoration:underline;}#yiv6016081564 .yiv6016081564attach {clear:both;display:table;font-family:Arial;font-size:12px;padding:10px 0;width:400px;}#yiv6016081564 .yiv6016081564attach div a {text-decoration:none;}#yiv6016081564 .yiv6016081564attach img {border:none;padding-right:5px;}#yiv6016081564 .yiv6016081564attach label {display:block;margin-bottom:5px;}#yiv6016081564 .yiv6016081564attach label a {text-decoration:none;}#yiv6016081564 blockquote {margin:0 0 0 4px;}#yiv6016081564 .yiv6016081564bold {font-family:Arial;font-size:13px;font-weight:700;}#yiv6016081564 .yiv6016081564bold a {text-decoration:none;}#yiv6016081564 dd.yiv6016081564last p a {font-family:Verdana;font-weight:700;}#yiv6016081564 dd.yiv6016081564last p span {margin-right:10px;font-family:Verdana;font-weight:700;}#yiv6016081564 dd.yiv6016081564last p span.yiv6016081564yshortcuts {margin-right:0;}#yiv6016081564 div.yiv6016081564attach-table div div a {text-decoration:none;}#yiv6016081564 div.yiv6016081564attach-table {width:400px;}#yiv6016081564 div.yiv6016081564file-title a, #yiv6016081564 div.yiv6016081564file-title a:active, #yiv6016081564 div.yiv6016081564file-title a:hover, #yiv6016081564 div.yiv6016081564file-title a:visited {text-decoration:none;}#yiv6016081564 div.yiv6016081564photo-title a, #yiv6016081564 div.yiv6016081564photo-title a:active, #yiv6016081564 div.yiv6016081564photo-title a:hover, #yiv6016081564 div.yiv6016081564photo-title a:visited {text-decoration:none;}#yiv6016081564 div#yiv6016081564ygrp-mlmsg #yiv6016081564ygrp-msg p a span.yiv6016081564yshortcuts {font-family:Verdana;font-size:10px;font-weight:normal;}#yiv6016081564 .yiv6016081564green {color:#628c2a;}#yiv6016081564 .yiv6016081564MsoNormal {margin:0 0 0 0;}#yiv6016081564 o {font-size:0;}#yiv6016081564 #yiv6016081564photos div {float:left;width:72px;}#yiv6016081564 #yiv6016081564photos div div {border:1px solid #666666;min-height:62px;overflow:hidden;width:62px;}#yiv6016081564 #yiv6016081564photos div label {color:#666666;font-size:10px;overflow:hidden;text-align:center;white-space:nowrap;width:64px;}#yiv6016081564 #yiv6016081564reco-category {font-size:77%;}#yiv6016081564 #yiv6016081564reco-desc {font-size:77%;}#yiv6016081564 .yiv6016081564replbq {margin:4px;}#yiv6016081564 #yiv6016081564ygrp-actbar div a:first-child {margin-right:2px;padding-right:5px;}#yiv6016081564 #yiv6016081564ygrp-mlmsg {font-size:13px;font-family:Arial, helvetica, clean, sans-serif;}#yiv6016081564 #yiv6016081564ygrp-mlmsg table {font-size:inherit;font:100%;}#yiv6016081564 #yiv6016081564ygrp-mlmsg select, #yiv6016081564 input, #yiv6016081564 textarea {font:99% Arial, Helvetica, clean, sans-serif;}#yiv6016081564 #yiv6016081564ygrp-mlmsg pre, #yiv6016081564 code {font:115% monospace;}#yiv6016081564 #yiv6016081564ygrp-mlmsg * {line-height:1.22em;}#yiv6016081564 #yiv6016081564ygrp-mlmsg #yiv6016081564logo {padding-bottom:10px;}#yiv6016081564 #yiv6016081564ygrp-msg p a {font-family:Verdana;}#yiv6016081564 #yiv6016081564ygrp-msg p#yiv6016081564attach-count span {color:#1E66AE;font-weight:700;}#yiv6016081564 #yiv6016081564ygrp-reco #yiv6016081564reco-head {color:#ff7900;font-weight:700;}#yiv6016081564 #yiv6016081564ygrp-reco {margin-bottom:20px;padding:0px;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ov li a {font-size:130%;text-decoration:none;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ov li {font-size:77%;list-style-type:square;padding:6px 0;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ov ul {margin:0;padding:0 0 0 8px;}#yiv6016081564 #yiv6016081564ygrp-text {font-family:Georgia;}#yiv6016081564 #yiv6016081564ygrp-text p {margin:0 0 1em 0;}#yiv6016081564 #yiv6016081564ygrp-text tt {font-size:120%;}#yiv6016081564 #yiv6016081564ygrp-vital ul li:last-child {border-right:none !important;}#yiv6016081564

NormThe mechanical  contraptions that I have out lined, should be very suitable for applying mechanical switches, timed to the stroke.I like the fact nothing can be hidden to view, happening in a mysterious
"Black box"as even discrete components in a circuit can be confusing.It would be so great to hear your further thoughts on this subject.Cheers Warren
Sent from Yahoo Mail on Android 
 
  On Fri, 16 Nov 2018 at 9:13 AM, Norman Wootan [email protected] [EVGRAY]<[email protected]> wrote:       
 

Mick, Ole, Kone etal!  I have been thinking a lot about my Locked Rotor experiments and did a lot of reading to come up with a fool proof Lenz free motor / generator combination which is so easy to build and proof test! First of all you should read what we know as facts! See the following articles:
 
https://www.motioncontroltips.com/faq-what-are-dc-shunt-motors-and-where-are-they-used/
 
http://www.machineryspaces.com/direct-current-motors.html
 
https://www.quora.com/What-will-happen-if-the-back-EMF-of-a-DC-motor-vanishes
 
https://www.youtube.com/watch?v=3-FPcKgwSzs&feature=youtu.be
 
https://www.youtube.com/watch?v=x3TFALmHtMw&feature=youtu.be
 
https://www.researchgate.net/post/A_DC_shunt_motor_is_running_at_light_load_what_happens_if_the_field_winding_gets_opened
 
Kone loves to play with the very powerful Neos as found at K&G Magnetics and shown in the video of the Ray's LENZ free generator.  What I will propose is very simple application of DC motor principles as read from the cited references. First you make your LENZ free  motor which is in reality a LINEAR MOTOR (Solenoid) which will give the necessary stroke length to drive the LINEAR generator (Coil oscillating within the drag free, LENZ free area of the Neo magnets).   Stroke of the solenoid is controlled by Hall sensor and IGBT drive switch to give an excursion rate (stroke) at a frequency of 60 HZ. By using a DC pulse  to drive the solenoid coil it is tricked into being in LOCKED ROTOR condition, thus no LENZ effect.  Has the light come on yet??   We know that Ray's generator puts out a sine wave output (AC) with no LENZ drag.  Following the DC motor principles as applied to the solenoid driver, you have a motor that is LENZ free also.  The combo should give an Over-unity output. Now the tricky part!  We know as Ole will agree in that when you switch the solenoid power to off state as magnetic flux is building toward saturation there will be a huge voltage spike (Neutral Spike) which we have to capture and not send to ground as ordinary practice in solid state switch design (snubber diodes)  The capture of the SPIKE energy (HV) which occurs naturally will be the over-unity factor here!  Interesting concept!  Think about it!  Norm    Mick! (accumulator HV caps)!
 
 On 11/16/2018 6:23 AM, Mick [email protected] [EVGRAY] wrote:
  
    
 
 
Ole,
 
I have had caps charge much faster in an LC tank than otherwise, but it could also have to do with noise in the core material as I was no using an air inductor.
 
 
 On 11/16/2018 1:19 AM, [email protected] [EVGRAY] wrote:
  
    
Hi Mick,
 
 "If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?"
 
 Yes that's correct.
 
 Common power factor correction in AC is for eliminating the reactive power that doesn't do any work but just heats the wires between the power plant and the reactive load. This is expensive for the owners of the power transmission lines and thus should be avoided. First storing the energy in a capacitor (or inductor or battery) and then dumping it to an active load will still make the power go in just one direction even though it happens in pulses. The energy is then moving from the source to the load. Reactive power has the energy moving to and from the load and power source. The power moving between the capacitor and inductor in an LC-tank is pure reactive except for the loss because of the parasitic resistance in the components and wires.
 
 Regards
 Ole
 
 
 ---In [email protected], <mkjekyll@...> wrote :
 
 
  
Ole,
 
Disregarding the issue at hand with the patent terminology and not concerning ourselves with the patent just a very high Q tank.
 
 
If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?
 

 
 

 
 On 11/15/2018 5:36 PM, onielsen@... [EVGRAY] wrote
  
 
    
I have only read to the following paragraph cited below. I wonder if the applicant knows about what he is writing.
 
 Citing paragraph 106 of the patent application (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
 "[0106] There is voltage across the inductor connected in series to the capacitor and there is voltage across the inductor connected in parallel to the capacitor. Since Power=voltage×current, a single power input produces two branches of electromagnetic power output, increasing the power output. In the alternative, the present disclosure may have one electromagnetic power output with less energy input."
 
 
 
 It isn't as simple as this. If using an oscilloscope for measuring the current and voltage it will show some phase displacement between the current and voltage which means reactive power. Look at the following small videos to see how one can be misled if not knowing how the phase between the current and voltage is: Only the the resistive part consumes (transforms) energy like R in figure 8.
 
 
     0:42     
Overunity Device Cop 2,5 ? explanation part 3.
   9.5K views5 years ago          1:01     
Overunity Device Cop 2,5 ? explanation part 2.
   10K views5 years ago          1:00      
Overunity Device Cop 2,5 ? part 1. but,
   8K views5 years ago    
 The numbers without the phase shift looks like overunity which isn't the case when taking into account the phase shift. Only real power is useful in doing work. Reactive power doesn't do work except for the small active part heating the the wires and other components because of their parasitic resistance. This part caused by current doing work against the resistance is active power and not actually reactive power. This is why the power distributing companies may charge costumers for having high reactive power going through their cables which heats the power lines without transferring active power to their costumers. It's just pure loss because the wires have resistance. Resistance converts electric power into heat.
 
 Just looked at the figures and found the description to figure 46:
 "[0149] FIG. 46 illustrates an embodiment of the present disclosure that conserves light bulb energy. In a test conducted, on Nov. 16, 1998, a light bulb was installed according to the schematic disclosed in FIG. 46 and is still running seven years later.
 
 [0150] Since Apparent Power (VA)=Current (A)×Voltage (V), the calculations below illustrate energy conservation for a 60 W light bulb. The voltage applied at the power input is 115 V. The apparent power for the Power Input Line (Line PIN) is measured at 126.5 VA. The apparent power measured for the shed motor fan is 126.5 VA and the apparent power measured for the light bulb is 65 VA. Therefore, 126 VA is measured at the input and a total of 191.5 VA is measured at the output, indicating an approximately 1.5 gain. Calculations are also shown for the energy savings for a 75W Bulb."
 
 It is the apparent power that is increased. The apparent power is the vector sum of the real power and the reactive power which makes it always greater than or equal to the real (or active or true) power.
 
 
 Source with description at: https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
 
 Regards
 Ole  
 
   
 
  
  #yiv6016081564 #yiv6016081564 -- #yiv6016081564ygrp-mkp {border:1px solid #d8d8d8;font-family:Arial;margin:10px 0;padding:0 10px;}#yiv6016081564 #yiv6016081564ygrp-mkp hr {border:1px solid #d8d8d8;}#yiv6016081564 #yiv6016081564ygrp-mkp #yiv6016081564hd {color:#628c2a;font-size:85%;font-weight:700;line-height:122%;margin:10px 0;}#yiv6016081564 #yiv6016081564ygrp-mkp #yiv6016081564ads {margin-bottom:10px;}#yiv6016081564 #yiv6016081564ygrp-mkp .yiv6016081564ad {padding:0 0;}#yiv6016081564 #yiv6016081564ygrp-mkp .yiv6016081564ad p {margin:0;}#yiv6016081564 #yiv6016081564ygrp-mkp .yiv6016081564ad a {color:#0000ff;text-decoration:none;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ygrp-lc {font-family:Arial;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ygrp-lc #yiv6016081564hd {margin:10px 0px;font-weight:700;font-size:78%;line-height:122%;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ygrp-lc .yiv6016081564ad {margin-bottom:10px;padding:0 0;}#yiv6016081564 #yiv6016081564actions {font-family:Verdana;font-size:11px;padding:10px 0;}#yiv6016081564 #yiv6016081564activity {background-color:#e0ecee;float:left;font-family:Verdana;font-size:10px;padding:10px;}#yiv6016081564 #yiv6016081564activity span {font-weight:700;}#yiv6016081564 #yiv6016081564activity span:first-child {text-transform:uppercase;}#yiv6016081564 #yiv6016081564activity span a {color:#5085b6;text-decoration:none;}#yiv6016081564 #yiv6016081564activity span span {color:#ff7900;}#yiv6016081564 #yiv6016081564activity span .yiv6016081564underline {text-decoration:underline;}#yiv6016081564 .yiv6016081564attach {clear:both;display:table;font-family:Arial;font-size:12px;padding:10px 0;width:400px;}#yiv6016081564 .yiv6016081564attach div a {text-decoration:none;}#yiv6016081564 .yiv6016081564attach img {border:none;padding-right:5px;}#yiv6016081564 .yiv6016081564attach label {display:block;margin-bottom:5px;}#yiv6016081564 .yiv6016081564attach label a {text-decoration:none;}#yiv6016081564 blockquote {margin:0 0 0 4px;}#yiv6016081564 .yiv6016081564bold {font-family:Arial;font-size:13px;font-weight:700;}#yiv6016081564 .yiv6016081564bold a {text-decoration:none;}#yiv6016081564 dd.yiv6016081564last p a {font-family:Verdana;font-weight:700;}#yiv6016081564 dd.yiv6016081564last p span {margin-right:10px;font-family:Verdana;font-weight:700;}#yiv6016081564 dd.yiv6016081564last p span.yiv6016081564yshortcuts {margin-right:0;}#yiv6016081564 div.yiv6016081564attach-table div div a {text-decoration:none;}#yiv6016081564 div.yiv6016081564attach-table {width:400px;}#yiv6016081564 div.yiv6016081564file-title a, #yiv6016081564 div.yiv6016081564file-title a:active, #yiv6016081564 div.yiv6016081564file-title a:hover, #yiv6016081564 div.yiv6016081564file-title a:visited {text-decoration:none;}#yiv6016081564 div.yiv6016081564photo-title a, #yiv6016081564 div.yiv6016081564photo-title a:active, #yiv6016081564 div.yiv6016081564photo-title a:hover, #yiv6016081564 div.yiv6016081564photo-title a:visited {text-decoration:none;}#yiv6016081564 div#yiv6016081564ygrp-mlmsg #yiv6016081564ygrp-msg p a span.yiv6016081564yshortcuts {font-family:Verdana;font-size:10px;font-weight:normal;}#yiv6016081564 .yiv6016081564green {color:#628c2a;}#yiv6016081564 .yiv6016081564MsoNormal {margin:0 0 0 0;}#yiv6016081564 o {font-size:0;}#yiv6016081564 #yiv6016081564photos div {float:left;width:72px;}#yiv6016081564 #yiv6016081564photos div div {border:1px solid #666666;min-height:62px;overflow:hidden;width:62px;}#yiv6016081564 #yiv6016081564photos div label {color:#666666;font-size:10px;overflow:hidden;text-align:center;white-space:nowrap;width:64px;}#yiv6016081564 #yiv6016081564reco-category {font-size:77%;}#yiv6016081564 #yiv6016081564reco-desc {font-size:77%;}#yiv6016081564 .yiv6016081564replbq {margin:4px;}#yiv6016081564 #yiv6016081564ygrp-actbar div a:first-child {margin-right:2px;padding-right:5px;}#yiv6016081564 #yiv6016081564ygrp-mlmsg {font-size:13px;font-family:Arial, helvetica, clean, sans-serif;}#yiv6016081564 #yiv6016081564ygrp-mlmsg table {font-size:inherit;font:100%;}#yiv6016081564 #yiv6016081564ygrp-mlmsg select, #yiv6016081564 input, #yiv6016081564 textarea {font:99% Arial, Helvetica, clean, sans-serif;}#yiv6016081564 #yiv6016081564ygrp-mlmsg pre, #yiv6016081564 code {font:115% monospace;}#yiv6016081564 #yiv6016081564ygrp-mlmsg * {line-height:1.22em;}#yiv6016081564 #yiv6016081564ygrp-mlmsg #yiv6016081564logo {padding-bottom:10px;}#yiv6016081564 #yiv6016081564ygrp-msg p a {font-family:Verdana;}#yiv6016081564 #yiv6016081564ygrp-msg p#yiv6016081564attach-count span {color:#1E66AE;font-weight:700;}#yiv6016081564 #yiv6016081564ygrp-reco #yiv6016081564reco-head {color:#ff7900;font-weight:700;}#yiv6016081564 #yiv6016081564ygrp-reco {margin-bottom:20px;padding:0px;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ov li a {font-size:130%;text-decoration:none;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ov li {font-size:77%;list-style-type:square;padding:6px 0;}#yiv6016081564 #yiv6016081564ygrp-sponsor #yiv6016081564ov ul {margin:0;padding:0 0 0 8px;}#yiv6016081564 #yiv6016081564ygrp-text {font-family:Georgia;}#yiv6016081564 #yiv6016081564ygrp-text p {margin:0 0 1em 0;}#yiv6016081564 #yiv6016081564ygrp-text tt {font-size:120%;}#yiv6016081564 #yiv6016081564ygrp-vital ul li:last-child {border-right:none !important;}#yiv6016081564

OK I looked at Ray's video, cancel my question. 

 Next question:
 

 Is it just a toy? can we get anything out of this. with those killer magnets?
 

 Ron

Hi Mick,

At resonance (in LC-tank) the capacitive impedance (imaginary part) cancels the inductive impedance (imaginary part) leaving only the resistance of the LC-tank circuit. The reactance of a capacitor is negative while the reactance of an inductor is positive. At resonance they are equal in magnitude but of opposite sign which cancel them out.

LC-tank: https://wiki2.org/en/LC_circuit https://wiki2.org/en/LC_circuit
Reactance: https://wiki2.org/en/Electrical_reactance https://wiki2.org/en/Electrical_reactance

Regards
Ole


---In [email protected], <mkjekyll@...> wrote :

 Ole,
 I have had caps charge much faster in an LC tank than otherwise, but it could also have to do with noise in the core material as I was no using an air inductor.
 
 
 On 11/16/2018 1:19 AM, onielsen@... mailto:onielsen@... [EVGRAY] wrote:
 
   Hi Mick,
 
 "If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?"
 
 Yes that's correct.
 
 Common power factor correction in AC is for eliminating the reactive power that doesn't do any work but just heats the wires between the power plant and the reactive load. This is expensive for the owners of the power transmission lines and thus should be avoided. First storing the energy in a capacitor (or inductor or battery) and then dumping it to an active load will still make the power go in just one direction even though it happens in pulses. The energy is then moving from the source to the load. Reactive power has the energy moving to and from the load and power source. The power moving between the capacitor and inductor in an LC-tank is pure reactive except for the loss because of the parasitic resistance in the components and wires.
 
 Regards
 Ole
 
 
 ---In [email protected] mailto:[email protected], <mkjekyll@...> mailto:mkjekyll@... wrote :
 
 
 Ole,
 Disregarding the issue at hand with the patent terminology and not concerning ourselves with the patent just a very high Q tank.
 
 If a reactive LC tank capacitor is then disconnected from the reactive source then discharged to a resistive load then reconnected energized back to the standing wave modality recharged disconnected discharged etc.  If the reactive energy is harvested in this manner are you claiming the same losses will occur as power factor correcting the reactive back into real power?
 
 
 
 
 On 11/15/2018 5:36 PM, onielsen@... mailto:onielsen@... [EVGRAY] wrote
 
   I have only read to the following paragraph cited below. I wonder if the applicant knows about what he is writing.
 
 Citing paragraph 106 of the patent application (https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf https://patentimages.storage.googleapis.com/53/7d/29/f7b4bd0194992d/US20070296373A1.pdf):
 "[0106] There is voltage across the inductor connected in series to the capacitor and there is voltage across the inductor connected in parallel to the capacitor. Since Power=voltage×current, a single power input produces two branches of electromagnetic power output, increasing the power output. In the alternative, the present disclosure may have one electromagnetic power output with less energy input."
 
 
 
 It isn't as simple as this. If using an oscilloscope for measuring the current and voltage it will show some phase displacement between the current and voltage which means reactive power. Look at the following small videos to see how one can be misled if not knowing how the phase between the current and voltage is: Only the the resistive part consumes (transforms) energy like R in figure 8.
 
 
 0:42 
 Overunity Device Cop 2,5 ? explanation part 3. 9.5K views5 years ago
 
 
 
 
 
 1:01 
 Overunity Device Cop 2,5 ? explanation part 2. 10K views5 years ago
 
 
 
 
 
 1:00 
 
 Overunity Device Cop 2,5 ? part 1. but, 8K views5 years ago
 
 
 
 
 The numbers without the phase shift looks like overunity which isn't the case when taking into account the phase shift. Only real power is useful in doing work. Reactive power doesn't do work except for the small active part heating the the wires and other components because of their parasitic resistance. This part caused by current doing work against the resistance is active power and not actually reactive power. This is why the power distributing companies may charge costumers for having high reactive power going through their cables which heats the power lines without transferring active power to their costumers. It's just pure loss because the wires have resistance. Resistance converts electric power into heat.
 
 Just looked at the figures and found the description to figure 46:
 "[0149] FIG. 46 illustrates an embodiment of the present disclosure that conserves light bulb energy. In a test conducted, on Nov. 16, 1998, a light bulb was installed according to the schematic disclosed in FIG. 46 and is still running seven years later.
 
 [0150] Since Apparent Power (VA)=Current (A)×Voltage (V), the calculations below illustrate energy conservation for a 60 W light bulb. The voltage applied at the power input is 115 V. The apparent power for the Power Input Line (Line PIN) is measured at 126.5 VA. The apparent power measured for the shed motor fan is 126.5 VA and the apparent power measured for the light bulb is 65 VA. Therefore, 126 VA is measured at the input and a total of 191.5 VA is measured at the output, indicating an approximately 1.5 gain. Calculations are also shown for the energy savings for a 75W Bulb."
 
 It is the apparent power that is increased. The apparent power is the vector sum of the real power and the reactive power which makes it always greater than or equal to the real (or active or true) power.
 
 
 Source with description at: https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/ https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/
 

(Message over 64 KB, truncated)

Version 2 

 https://www.youtube.com/watch?v=tRROFwwz5hQ https://www.youtube.com/watch?v=tRROFwwz5hQ
 

 Ron

H Sven,

"I have now wrapped all power lines with aluminum foil and this one-sided grounded."
Just be careful how the grounds are connected. Here are some EMC tutorial articles: http://learnemc.com/emc-tutorials http://learnemc.com/emc-tutorials

The current paths may still induce currents into other circuit parts when the current carrying wires form loops having enough area (i.e. one turn coils). Shielding that way doesn't help for magnetic fields. The signal wires would probably improve if screened cable was used. But it all depends on how the wires are rigged up to avoid loops transmitting and receiving magnetic fields (magnetic coupling).

"...the high-power mosfets are very hot although they are used at most 10%. The cut-off voltage at the drain increases in the kilovolt range when the transverter is connected"
What do you mean by 'used at most 10%?' When getting hot they may need more cooling or they are used at their maximum power dissipation. Remember the power dissipation given in the datasheet is normally when the surface of the device is held at 20 degree Celsius which is only possible when using water cooling or heavy forced air cooling like pressurized air flow. If the drain-source voltage is reaching the avalanche breakdown voltage of the MOSFETs this will dissipate a lot of heat in them. Also switching high voltages at high current gives great switching loss if the switching transitions take too long. During switching transitions the MOSFETs are working in the linear region which means both voltage across and current through them at the same time. This dissipates heat as voltage times current gives power [V x A = W]. Multiply this by the transition time to get energy dissipation [W x s = J]. Look at the gate source signal as this controls the drain source channel.

Have you found out how to make free energy or is it still just reactive power?

I have made some simple experiments along the way of Pierre Cotnoir's device. I may have simplified it too much as I used a bunch of small transformers instead of a motor stator as in Pierre's device. No excess power output was observed. My next experiment is along the way of the Clemente Figuera patents (http://alpoma.net/tecob/?page_id=8258 http://alpoma.net/tecob/?page_id=8258). He may actually mix the fields the right way for coherence to occur. This could also be the way Alfred Hubbard's device worked.

Regards
Ole

 

---In [email protected], <s.friedrich@...> wrote :

 Hello to all those interested, I have now built a push-pull inverter for the transverter anti-drive to drive it. From 37 Hz 650Hz is fully adjustable and the pulse width.
A simple square wave signal is generated and sent. It works wonderfully. The interference is a problem when switching 350V peaks. I have now wrapped all power lines with aluminum foil and this one-sided grounded. The boards I will install in an aluminum housing and also this ground, the disturbances are almost all gone. By shielding, the energy is no longer emitted and remains in the lines apparently, since the shielding, the high-power mosfets are very hot although they are used at most 10%. The cut-off voltage at the drain increases in the kilovolt range when the transverter is connected. The complete line to Transverter is also shielded. I now wanted to build an Energy Recovery Snubber to recycle that energy. First test show that you can drive the transverter so much more efficient. I have to build this inverter even more reliable or change.
Best regards
Sven

Norm, 

 What is Ray doing in Version 2, varying the magnetic field?
 

 Is this somewhat similar to Clemente Figuera?
 

 Ron