Re: [EVGRAY] Triple thick BiTT

Check out this inductor from before Noah’s flood with ceramic or stone core. 
https://youtu.be/Jrg65rkvOjM
Very interesting!

Thank you for all of your hard work. 
Timothy Searfoss

> On Jan 20, 2018, at 11:44, 'Douglas L. Konzen' [email protected] [EVGRAY] <[email protected]> wrote:
> 
> The rectangular outer part of core has now three times the thickness than the center primary section to make sure backnemf flux from secondary A has good pathway to follow andflow into opposite side secondary B
> 
> Get Outlook for Android
> 
> 
> <20180120_193231.jpg>

See one of the photos of the very old inductor. 




Timothy Searfoss

> On Jan 20, 2018, at 11:44, 'Douglas L. Konzen' [email protected] [EVGRAY] <[email protected]> wrote:
> 
> The rectangular outer part of core has now three times the thickness than the center primary section to make sure backnemf flux from secondary A has good pathway to follow andflow into opposite side secondary B
> 
> Get Outlook for Android
> 
> 
> <20180120_193231.jpg>

The rectangular outer part of core has now three times the thickness than the center primary section to make sure backnemf flux from secondary A has good pathway to follow andflow into opposite side secondary B

Get Outlook for Android<https://aka.ms/ghei36>

Hi Timothy
 I watched the video of the 20K old transformer - sorry I don't believe it only because of the four light socket holes which I am sure they would not of had 20K years ago and I would bet this is leftover stuff from bombings and the war in Kosove and stone metled from some high tech bombs......however I am sure the Egyptians and ancient Iraqis had electric lights, and probably many civilizations more advanced than outs have lived and died the past million years...
 ciaoKone

Hi Doug,
That looks good, hope it goes well.



On Sun, Jan 21, 2018 at 3:44 AM, 'Douglas L. Konzen' [email protected]
[EVGRAY] <[email protected]> wrote:

>
>
> The rectangular outer part of core has now three times the thickness than
> the center primary section to make sure backnemf flux from secondary A has
> good pathway to follow andflow into opposite side secondary B
>
> Get Outlook for Android <https://aka.ms/ghei36>
>
>
>
> 
>

Hello Douglas,

I hope you succeed, or in the end, nothing comes to energy. The load on the two secondary connections reduces the magnetization so the primary must be increased again so that the energy can be transferred again. The principle is the same or similar to the Jensen or Markov transformer.

It would be really great if you could build an OU device with such simple means.

regards

Sven

Hi Sven
 I do not think exactly  that the load on the seconaries in a BiTT "reduces the magnetism" but rather the inherent backemf forces that usually will reflect back to the primary are given an "alternate road" and magnetic pahtway tto follow, and that is to go right over and across the primary,into the opposing secondary which gives more power to output of secondaues as well as "reducing the magnetism" in the primary (no reflection of power to the primary)...so nothing diminished, it is just re-routed to not affect the primary...
 This attempt to explain the 8W output and 4 W input in Kurt Kokinenes video, as where does that 4 W come from??:
 https://www.youtube.com/watch?v=cm-YQdfEqBA https://www.youtube.com/watch?v=cm-YQdfEqBA

Hi Kone,

"This attempt to explain the 8W output and 4 W input in Kurt Kokinenes video..."
Don't believe his calculations that aren't based on measurements. He calculates the resistance of the LED lamp to be 33 Ohm at 12V. But Kurt actually applies 16.95V to the lamp. LEDs are diodes which are very nonlinear devices. To drive them with a voltage like 12V they must have a series resistor or a regulator to limit the current. If not doing so even a slight change in the voltage gives a big change in the current. Thus the 33 Ohm at 12V will change when applying 16.95V to the lamp. He should have measured the current at 16.95V to calculate the resistance at that voltage and current. If the lamp has a high efficient regulator built in its consumption will stay almost constant. If having resistors to dump the excess voltage its consumption is bigger than what was calculated. Thus no useful conclusion can be drawn with the limited data available.

Regards
Ole
 

---In [email protected], <konehead@...> wrote :

 Hi Sven
 I do not think exactly  that the load on the seconaries in a BiTT "reduces the magnetism" but rather the inherent backemf forces that usually will reflect back to the primary are given an "alternate road" and magnetic pahtway tto follow, and that is to go right over and across the primary,into the opposing secondary which gives more power to output of secondaues as well as "reducing the magnetism" in the primary (no reflection of power to the primary)...so nothing diminished, it is just re-routed to not affect the primary...
 This attempt to explain the 8W output and 4 W input in Kurt Kokinenes video, as where does that 4 W come from??:
 https://www.youtube.com/watch?v=cm-YQdfEqBA https://www.youtube.com/watch?v=cm-YQdfEqBA

SvenYes, simplicity equals elegance in design.Unfortunately that simplicity must get very complicated first to understand what is happening.Cheers Warren

Sent from Yahoo Mail on Android 
 
  On Sun, Jan 21, 2018 at 7:28 AM, [email protected] [EVGRAY]<[email protected]> wrote:       

Hello Douglas,

I hope you succeed, or in the end, nothing comes to energy. The load on the two secondary connections reduces the magnetization so the primary must be increased again so that the energy can be transferred again. The principle is the same or similar to the Jensen or Markov transformer.

It would be really great if you could build an OU device with such simple means.

regards

Sven
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Hi Ole
 Other BiTT demos on youtube show X3 watts out compared to in, so maybe Kurt is being conservative in how he measures actually.
 I am to a ltitle bit disappointed he did not just put an anlog and/or digital mulmeter reading the amps into that LED light.  
 But when I work with LEDs analog will give the same reading as multimeters so if analog it is simply a resistive load (heat) applied inside the meter and needle goes up correspondingly so it really does not bother me too much he did not do a meter.;
 You say if limiting circuit to limit current in the LED the current remains constant -  I would call it in my limited understanding  (almopst a pun haha)  current is  "limited" to a certain level actually that the LED circuit  will not permit itself to pull into itself....if say only 8V applied, the current will be lower, if 17V the current will be at its maximum allowed so I don't see what your point is here! (seems to me at least sorry)
  If resistorsi there to limit currentr, that is part of the resistance of the LED given already, and like you say there will be MORE corrent than he shows if so, so again I dojnt see the point....
 .
 Also if the non-linear character of LED lights/diodes does affect the current when more voltage is applied then it is rated at, what would be the "percentage" of difference from ohms-law calculated watts? 10%? 20%? even if 50% change in the current being lower than calculated with ohms law, it is still "unity" 
 

 Kurt does show the primary is not affected by the loading of secondaries and that in itself is pretty good expecially compared to standard transformers...
 ciao
 Kone

Hi Kone,

"You say if limiting circuit to limit current in the LED the current remains constant"
If it has a build in switching regulator the current decrease when the voltage increase. This makes the power stay constant. Without any measurement or datasheet of the LED lamp we just don't know.

"if say only 8V applied, the current will be lower"
Yes. Perhaps not even enough current will flow to make the lamp light.

Take a look at the voltage current characteristics of some white LEDs at the following figure taken from here: https://www.maximintegrated.com/en/app-notes/index.mvp/id/3070 https://www.maximintegrated.com/en/app-notes/index.mvp/id/3070


Figure 7. These curves illustrate the considerable differences in current-voltage characteristics for white LEDs, even those randomly selected from the same production lot. Operating several such LEDs in parallel at a constant 3.3V (the upper dotted line) therefore produces different shades of white and different brightnesses.

A 12V LED lamp may have 3 LEDs in series and a resistor to drop the remaining voltage. At 8V each LED will get below 3V which may not make them light up.

"Also if the non-linear character of LED lights/diodes does affect the current when more voltage is applied then it is rated at, what would be the "percentage" of difference from ohms-law calculated watts?"
The datasheet of the LED is needed to know this. He could make his own curve for the particular LED lamp by measuring the voltage and current at different values. Or he could just make a measurement at the particular voltage of interest (16.95V) to know.

Regards
Ole
 

---In [email protected], <konehead@...> wrote :

 Hi Ole
 Other BiTT demos on youtube show X3 watts out compared to in, so maybe Kurt is being conservative in how he measures actually.
 I am to a ltitle bit disappointed he did not just put an anlog and/or digital mulmeter reading the amps into that LED light. 
 But when I work with LEDs analog will give the same reading as multimeters so if analog it is simply a resistive load (heat) applied inside the meter and needle goes up correspondingly so it really does not bother me too much he did not do a meter.;
 You say if limiting circuit to limit current in the LED the current remains constant -  I would call it in my limited understanding  (almopst a pun haha)  current is  "limited" to a certain level actually that the LED circuit  will not permit itself to pull into itself....if say only 8V applied, the current will be lower, if 17V the current will be at its maximum allowed so I don't see what your point is here! (seems to me at least sorry)
  If resistorsi there to limit currentr, that is part of the resistance of the LED given already, and like you say there will be MORE corrent than he shows if so, so again I dojnt see the point....
 .
 Also if the non-linear character of LED lights/diodes does affect the current when more voltage is applied then it is rated at, what would be the "percentage" of difference from ohms-law calculated watts? 10%? 20%? even if 50% change in the current being lower than calculated with ohms law, it is still "unity" 
 

 Kurt does show the primary is not affected by the loading of secondaries and that in itself is pretty good expecially compared to standard transformers...
 ciao
 Kone

The figure went missing here it is (hopefully) else the link to it:
https://www.maximintegrated.com/en/images/appnotes/3070/3070Fig07.gif https://www.maximintegrated.com/en/images/appnotes/3070/3070Fig07.gif


Regards
Ole


---In [email protected], <onielsen@...> wrote :

 Hi Kone,

"You say if limiting circuit to limit current in the LED the current remains constant"
If it has a build in switching regulator the current decrease when the voltage increase. This makes the power stay constant. Without any measurement or datasheet of the LED lamp we just don't know.

"if say only 8V applied, the current will be lower"
Yes. Perhaps not even enough current will flow to make the lamp light.

Take a look at the voltage current characteristics of some white LEDs at the following figure taken from here: https://www.maximintegrated.com/en/app-notes/index.mvp/id/3070 https://www.maximintegrated.com/en/app-notes/index.mvp/id/3070


Figure 7. These curves illustrate the considerable differences in current-voltage characteristics for white LEDs, even those randomly selected from the same production lot. Operating several such LEDs in parallel at a constant 3.3V (the upper dotted line) therefore produces different shades of white and different brightnesses.

A 12V LED lamp may have 3 LEDs in series and a resistor to drop the remaining voltage. At 8V each LED will get below 3V which may not make them light up.

"Also if the non-linear character of LED lights/diodes does affect the current when more voltage is applied then it is rated at, what would be the "percentage" of difference from ohms-law calculated watts?"
The datasheet of the LED is needed to know this. He could make his own curve for the particular LED lamp by measuring the voltage and current at different values. Or he could just make a measurement at the particular voltage of interest (16.95V) to know.

Regards
Ole
 

---In [email protected], <konehead@...> wrote :

 Hi Ole
 Other BiTT demos on youtube show X3 watts out compared to in, so maybe Kurt is being conservative in how he measures actually.
 I am to a ltitle bit disappointed he did not just put an anlog and/or digital mulmeter reading the amps into that LED light. 
 But when I work with LEDs analog will give the same reading as multimeters so if analog it is simply a resistive load (heat) applied inside the meter and needle goes up correspondingly so it really does not bother me too much he did not do a meter.;
 You say if limiting circuit to limit current in the LED the current remains constant -  I would call it in my limited understanding  (almopst a pun haha)  current is  "limited" to a certain level actually that the LED circuit  will not permit itself to pull into itself....if say only 8V applied, the current will be lower, if 17V the current will be at its maximum allowed so I don't see what your point is here! (seems to me at least sorry)
  If resistorsi there to limit currentr, that is part of the resistance of the LED given already, and like you say there will be MORE corrent than he shows if so, so again I dojnt see the point....
 .
 Also if the non-linear character of LED lights/diodes does affect the current when more voltage is applied then it is rated at, what would be the "percentage" of difference from ohms-law calculated watts? 10%? 20%? even if 50% change in the current being lower than calculated with ohms law, it is still "unity" 
 

 Kurt does show the primary is not affected by the loading of secondaries and that in itself is pretty good expecially compared to standard transformers...
 ciao
 Kone

I have told a billion times biTT is base in using 3 phase transformers as ferroresonant ones  ... and external windings & horseshoe core loops to it .
related to magnetotransistor  revealed in JNL groups and PATENTED as MEG by bearden .....


reread all my post in regards to it ... and its the reason i no longer answer personal technical questions if its not within a forum,( that was not a subject to get a patent on it) .... do you people know what a magnetic diode is ? and its function as a diac in magneto amplification ....?

I can bet my dick put in a meatgrinder most of you people dont !

(H)

DougThat was a led, and not a quartz lamp?I find old fashioned tungsten bulbs are pretty close to what they say they are drawing. Using those Edison bulb to two pin adapters, in a power strip works for me, as a great test set up that is very easy to use as a load that can be incrementally adjusted with a good visual feedback of just what is going on.
With 40 watt clear appliance bulbs, they stay cool enough to pull out, or push in as required. 40 watts is a handy increment, though you can also get 10 watt bulbs.In Ontario, 100 watt bulbs are getting scarce on the shelves in tungsten, though one can get quartz, like perhaps Kurt had. Those hot little bulbs come in 150 and 300 watts and get used for mini pot lights recessed in ceilings.Back in the early seventies, I used them for lighting models and miniatures, getting Kodak Caresel slide projector bulbs.Cheers Warren
Sent from Yahoo Mail on Android 
 
  On Sun, Jan 21, 2018 at 10:37 AM, [email protected] [EVGRAY]<[email protected]> wrote:       


Hi Ole

Other BiTT demos on youtube show X3 watts out compared to in, so maybe Kurt is being conservative in how he measures actually.

I am to a ltitle bit disappointed he did not just put an anlog and/or digital mulmeter reading the amps into that LED light.  

But when I work with LEDs analog will give the same reading as multimeters so if analog it is simply a resistive load (heat) applied inside the meter and needle goes up correspondingly so it really does not bother me too much he did not do a meter.;

You say if limiting circuit to limit current in the LED the current remains constant -  I would call it in my limited understanding  (almopst a pun haha)  current is  "limited" to a certain level actually that the LED circuit  will not permit itself to pull into itself....if say only 8V applied, the current will be lower, if 17V the current will be at its maximum allowed so I don't see what your point is here! (seems to me at least sorry)

 If resistorsi there to limit currentr, that is part of the resistance of the LED given already, and like you say there will be MORE corrent than he shows if so, so again I dojnt see the point....

.

Also if the non-linear character of LED lights/diodes does affect the current when more voltage is applied then it is rated at, what would be the "percentage" of difference from ohms-law calculated watts? 10%? 20%? even if 50% change in the current being lower than calculated with ohms law, it is still "unity" 




Kurt does show the primary is not affected by the loading of secondaries and that in itself is pretty good expecially compared to standard transformers...

ciao

Kone






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Hi Hector,

Nikola Tesla had a patent on how to rectify AC using magnetic amplifiers (or using the magnetic nonlinear conductance of iron that happens when it goes into saturation):
https://teslauniverse.com/nikola-tesla/patents/us-patent-413353-method-obtaining-direct-alternating-currents https://teslauniverse.com/nikola-tesla/patents/us-patent-413353-method-obtaining-direct-alternating-currents



Magnetic amplifiers:

How To #1 - Magnetic Amplifier & Saturable Reactor - Demo & Basic Principle Of Operation  (7:20)
https://www.youtube.com/watch?v=lB3HBoKPbOQ https://www.youtube.com/watch?v=lB3HBoKPbOQ (7:20)
Magnetic Amplifier:
https://www.youtube.com/watch?v=lk2f5DCbyXg https://www.youtube.com/watch?v=lk2f5DCbyXg (2:14).

Regards
Ole


---In [email protected], <arkresearch@...> wrote :

 I have told a billion times biTT is base in using 3 phase transformers as ferroresonant ones  ... and external windings & horseshoe core loops to it .
related to magnetotransistor  revealed in JNL groups and PATENTED as MEG by bearden .....


reread all my post in regards to it ... and its the reason i no longer answer personal technical questions if its not within a forum,( that was not a subject to get a patent on it) .... do you people know what a magnetic diode is ? and its function as a diac in magneto amplification ....?

I can bet my dick put in a meatgrinder most of you people dont !

(H)

Hi hector
 I will bet my dong a magnetic diode is something that blocks magnetic flux to flow through a core material in one direction, but allows it to flow the other direction...for example in the Beardan MEG he sticks a magnet in or on the core-leg, permitting AC flux in this transformer leg to go one way {through the magnet) that the magnet's polarity allows, but not the other way....
 As for diac in magneto amplification, I know what a magneto is, and to amplify the power or voltage in a magneto, you can stick a magnet of the correct polarity onto the back-end of the magneto's core  and this creates a stronger flux in the core, and you get more power or voltages, but the magnet needs to face the right way in polarity for this to work - similar to getting more speed and power from a DC pulsed motor by putting magnets back behind the cores of the motor coils (but again must face correct polarity or motor slows)....AKA "regauging magnets" which is similar but does more than just strengthen the flux in the core.....will not get into regauging now...
 So am I right? Let me know eh!
 As for the BiTT it is not the Beardan MEG (farts and dies under load!) and it is not the other stuff that might employ some sort of 
magnetic diode/external horseshoe cores/magneto transistors (where cores work like transistor switch in how magnetic flux flows and switches on or off ???)...
 Instead the BiTT is very simple and just gives a lower-magnetic resistance PATHWAY to magnetic backemf  and it happily flows over to the opposite side secondary (instead of back to the primary)
 So the secondaries become ADDITIVE to power produced, not "BLOCKING" or "BUCKING" magnetic flux flow that reflects back to primary and gives extra draw to primary when secondaries load.
 IF tryibng to do this with a 3ph transfiormer, it wont work unless you add a horeshoe or similar shape core leg to top and bottom of core, and this added core shapes should be much thicker than the 3ph transformer's existing cores, otherwise the flux will not want to ride the easy road back to the opposite side secondary....maybe this is what you are saying I don't know...
 ciao
 Kojne

Hi Warren
 I think LED lights, but maybe quartz??
 I am trying to get a hold of Kurt - I guess he lives up near you in Toronto someone told me today....
 I looked up LED lights on ebay tonight, trying to find the one he used...but could not find same looking type just ones similar-looking....
 

 tried to read the writing on the base he shows - it is hard to read...took photo and blew it up still could not read it but looks like it says 12V and 300ma - so if so, and that bulb only pulls 300ma "no matter what" then approx. 18Vdc X .3A = 5.4W still OU but not so much.... 
 ciao
 Kone

Hi Ole
 I am trying to contact Kurt to find all this out for sure....
 ciaoKone

Hello Douglas,

I know that the reflection on the primary winding should be prevented and I've already looked at the principle. But what prevents the reflection can also reduce or prevent the energy transfer to the secondary winding.

I still think the idea is good. Have now again a test run with the new config. everything stays tepid. Despite all this, a diode broke again for me. At the beginning I forgot to connect a cable for the discharge of the negative diode plug a page was interrupted as last time I am also a diode broke.

I've already broken my capacitance meter again I had overlooked a residual voltage. I curse those things that are so sensitive. My Fluke does everything with but only max. Measure 5 μF.

I have now exchanged some capacitors to get symmetry in the capacitances.

I have now. e.g. 14.86 μf and 14.84 μF more does not show my device. How can I get to Hector's 0.003 only.

regards

Sven

Hi Warren
 Actually it is 360ma that his bulb shows written on the base, and 12Vdc.......
 So if 16.92V (not approx. 18 like I wrote) that comes to 16.95Vdc X .36A = 
 6.1 Watts output compared to the .39 X 12V input of 4.68Watts
 I just assumed that is an LED, I don't know! maybe it is not and all the LED characteristics of over-voltage and what happens to current  just do not matter....
 He uses what looks like four LEDs he says of 3W each in his other video, to get a 12W load these look smaller but do not know for sure...
 ciaoKone