AW: Re: Aw: Re: AW: [EVGRAY] Re: buck plug ...

Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven

Von Samsung Mobile gesendet

-------- Ursprüngliche Nachricht --------
Von: "[email protected] [EVGRAY]" <[email protected]> 
Datum:15.02.2018  00:51  (GMT+01:00) 
An: [email protected] 
Betreff: Re: Aw: Re: AW: [EVGRAY] Re: buck plug ... 

Hi Sven,

The circuits in the links are just variable phase controllers. They won't detect when the peak is reached.

Perhaps another way would be to monitor the charging voltage or current and find all the zero crossings. The trigger signal could then be filtered by some logic gates that triggers each time the capacitors would be max charged in each cycle. This would trig no matter the amount of charge the capacitors actually receive.

Regards
Ole




---In [email protected], <s.friedrich@...> wrote :

Hi Ole,

I again, this topic with the ignition does not let me go.
I have found a pdf here and this circuit, what do you think of it is there still room for improvement for my diode plug igniter?

regards

Sven
 
Gesendet: Mittwoch, 14. Februar 2018 um 19:18 Uhr
Von: "'Sven Friedrich' s.friedrich@... [EVGRAY]" <[email protected]>
An: [email protected]
Betreff: Aw: Re: AW: [EVGRAY] Re: buck plug ...
 
 

Hello Ole,

could you make improvements to the phase control, you have my drawings yes.

I have taken over from jöretronik, but then with potentiometers at R2 and P used.

I have now seen circuits where a potentiometer is connected directly to the trigger capacitor or with resistor, one has advantages?

Maybe it's just because of my Thyristorzündung that the thyristor can not ignite later.

regards

Sven
 
http://www.joretronik.de/Web_NT_Buch/Kap4/Kapitel4.html
 
https://de.wikipedia.org/wiki/Phasenanschnittsteuerung#/media/File:Phase_control_schematics.svg
 
Gesendet: Mittwoch, 14. Februar 2018 um 14:57 Uhr
Von: "'Sven Friedrich' s.friedrich@... [EVGRAY]" <[email protected]>
An: [email protected]
Betreff: Aw: Re: AW: [EVGRAY] Re: buck plug ...
 
 

Hi Ole,

I said what else could I test on the transverter to get positive results or adjust.

I try again to make all components the same as possible or adapt.

I always have better performance with negative diode plugs, no matter how I change the polarity or the capacitors. The average power and peak is always much higher there, sometimes 15 to 20 volts, so I do not get natural synchronicity with the main LC.

regards

Sven
 
Gesendet: Mittwoch, 14. Februar 2018 um 13:59 Uhr
Von: "onielsen@... [EVGRAY]" <[email protected]>
An: [email protected]
Betreff: Re: AW: [EVGRAY] Re: buck plug ...
 
Hi Sven,

"Do you have any idea what I could try?"
I lost you here. Idea to peak detector or stable output or what?

Regards
Ole



---In [email protected], <s.friedrich@...> wrote :
 
Hi Ole,

I do not understand that completely, finally we have an alternating field and the polarity is constantly changing.

Do you have any idea what I could try?

regards

Sven

Hi Sven,

Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.

The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.

A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.

Regards
Ole
 

---In [email protected], <s.friedrich@...> wrote :

 

 Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven
 

 Von Samsung Mobile gesendet
...

Hi Sven,
 
 Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.
 
 The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.
 
 A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.
 
 Regards
 Ole
 

---In [email protected], <onielsen@...> wrote :

 Hi Sven,

Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.

Third time.

Hi Sven,
 
 Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.
 
 The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.
 
 A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.
 
 Regards
 Ole
 

---In [email protected], <s.friedrich@...> wrote :

 

 Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven
 

 Von Samsung Mobile gesendet

...

Empty body

Hi Ole,

I revised the circuit again. The freewheeling diodes with the incandescent lamps, I've never installed anyway, if it works at all.
The connection diodes between the inductor and capacitor I have removed and the snubber capacitors on the thyristors, the vibrations are now gone for the time being.

For me, the diodes are just as charged or discharged as on the other side or have I overlooked something!?!

I took a few scope pictures and documented the circuit.

regards

Sven

Hi Sven,

"When D1 is loaded there is the positive half wave and at D3 the negative half wave. This means for me if D1 is no longer loaded, then D3 is then loaded because the polarity yes changes. In principle, I load with both half-waves like a FWBR. And, of course, the charged inductor L1 continues to draw current through diode D3 until it is discharged. OK."

The diode plug is not connected like an ordinary full bridge rectifier. Each half of the circuit is connected in common to one of the AC legs. The normal bridge rectifier DC output use the positive and negative legs only and the AC input is connected to the other two legs only. When D3 is conducting (current going through it) the current cannot come from AC as there is no return path for the current. The only return paths to AC are through D1 or D2. No one of these paths are possible.

When charging C1 from AC the current takes the path through D1, L1 the diode without name which isn't really needed then through C1 and back to AC. As the current goes through L1 it magnetizes L1. When the voltage from AC decreases towards zero L1 will start demagnetizing. This makes the current continue at the level it reached when the voltage starts to decrease from its peak value (or actually later because of the phase shift). When AC reaches 0 Volt D3 isn't reverse biased any longer. When AC gets negative U_pos is limited to the forward conduction voltage of around 0.7V to 1V or more of D3. U_pos is then -0.7V to -1V. This voltage is coming from the current through L1 that now decreases as L1 is demagnetizing. L1 now has positive voltage at its right end and negative U_pos (= -0.7V) at its left end. When the demagnetizing current of L1 stops running the voltage across L1 is zero. If the diode without name wasn't there (shorted) the voltage at both ends of L1 is then same as the voltage across C1 (U_pos = .voltage across C1). This makes the negative voltage across D3 disappear. Even when the diode without any name is there the voltage U_pos across D3 can't be negative. This can be used as information for knowing when the capacitor C1 is fully charged during a half cycle from AC.

The end of the signal where U_pos is negative then indicates when C1 has reached its peak voltage. Thus a proper designed trigger circuit will be able to fire the SCR T1 from monitoring the voltage across D3: The same applies for the bottom half part of the circuit but having the signs reversed. The line connecting D3, D4 C1 and C2 is the reference point for both half part trigger circuits.


Regards
Ole
 

---In [email protected], <s.friedrich@...> wrote :

   Hi Ole,
 
 I do not quite get along with it now. We have an alternating voltage of positive half-wave and negative half-wave.
 
 When D1 is loaded there is the positive half wave and at D3 the negative half wave. This means for me if D1 is no longer loaded, then D3 is then loaded because the polarity yes changes. In principle, I load with both half-waves like a FWBR. And, of course, the charged inductor L1 continues to draw current through diode D3 until it is discharged. OK.
 
 I think so soon when I discharge the thyristors so, it may be that they recharge themselves and the SCR does not turn off and everything collapses, you would have to delay again, perhaps through suppressor diodes possibly!?!
 
 I can connect the Scope to both diodes, to be honest, I just see that you can replace the 4 diodes with a FWBR what makes everything a little more compact, I think, I did not even recognize that. laughing
 
 regards
 
 Sven Gesendet: Donnerstag, 15. Februar 2018 um 03:41 Uhr
 Von: "onielsen@... [EVGRAY]" <[email protected]>
 An: [email protected]
 Betreff: Re: AW: Re: Aw: Re: AW: [EVGRAY] Re: buck plug ...
    
 Third time.
 
 Hi Sven,
 
 Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.
 
 The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.
 
 A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.
 
 Regards
 Ole
 
 
 ---In [email protected], <s.friedrich@...> wrote :
    
 Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven
  
 Von Samsung Mobile gesendet

 ...

H Sven,

I wonder why Yahoo sometimes allows pasting .jpg .gif and .png images while at other times the posts get truncated from where the image is supposed to be?

"When D1 is loaded there is the positive half wave and at D3 the negative half wave. This means for me if D1 is no longer loaded, then D3 is then loaded because the polarity yes changes. In principle, I load with both half-waves like a FWBR. And, of course, the charged inductor L1 continues to draw current through diode D3 until it is discharged. OK."
 
 The diode plug is not connected like an ordinary full bridge rectifier. Each half of the circuit is connected in common to one of the AC legs. The normal bridge rectifier DC output use the positive and negative legs only and the AC input is connected to the other two legs only. When D3 is conducting (current going through it) the current cannot come from AC as there is no return path for the current. The only return paths to AC are through D1 or D2. No one of these paths are possible.
 
 When charging C1 from AC the current takes the path through D1, L1 the diode without name which isn't really needed then through C1 and back to AC. As the current goes through L1 it magnetizes L1. When the voltage from AC decreases towards zero L1 will start demagnetizing. This makes the current continue at the level it reached when the voltage starts to decrease from its peak value (or actually later because of the phase shift). When AC reaches 0 Volt D3 isn't reverse biased any longer. When AC gets negative U_pos is limited to the forward conduction voltage of around 0.7V to 1V or more of D3. U_pos is then -0.7V to -1V. This voltage is coming from the current through L1 that now decreases as L1 is demagnetizing. L1 now has positive voltage at its right end and negative U_pos (= -0.7V) at its left end. When the demagnetizing current of L1 stops running the voltage across L1 is zero. If the diode without name wasn't there (shorted) the voltage at both ends of L1 is then same as the voltage across C1 (U_pos = .voltage across C1). This makes the negative voltage across D3 disappear. Even when the diode without any name is there the voltage U_pos across D3 can't be negative. This can be used as information for knowing when the capacitor C1 is fully charged during a half cycle from AC.
 
 The end of the signal where U_pos is negative then indicates when C1 has reached its peak voltage. Thus a proper designed trigger circuit will be able to fire the SCR T1 from monitoring the voltage across D3: The same applies for the bottom half part of the circuit but having the signs reversed. The line connecting D3, D4 C1 and C2 is the reference point for both half part trigger circuits.
 
 Regards
 Ole
 

---In [email protected], <s.friedrich@...> wrote :

   Hi Ole,
 
 I do not quite get along with it now. We have an alternating voltage of positive half-wave and negative half-wave.
 
 When D1 is loaded there is the positive half wave and at D3 the negative half wave. This means for me if D1 is no longer loaded, then D3 is then loaded because the polarity yes changes. In principle, I load with both half-waves like a FWBR. And, of course, the charged inductor L1 continues to draw current through diode D3 until it is discharged. OK.
 
 I think so soon when I discharge the thyristors so, it may be that they recharge themselves and the SCR does not turn off and everything collapses, you would have to delay again, perhaps through suppressor diodes possibly!?!
 
 I can connect the Scope to both diodes, to be honest, I just see that you can replace the 4 diodes with a FWBR what makes everything a little more compact, I think, I did not even recognize that. laughing
 
 regards
 
 Sven Gesendet: Donnerstag, 15. Februar 2018 um 03:41 Uhr
 Von: "onielsen@... [EVGRAY]" <[email protected]>
 An: [email protected]
 Betreff: Re: AW: Re: Aw: Re: AW: [EVGRAY] Re: buck plug ...
    
 Third time.
 
 Hi Sven,
 
 Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.
 
 The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.
 
 A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.
 
 Regards
 Ole
 
 
 ---In [email protected], <s.friedrich@...> wrote :
    
 Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven
  
 Von Samsung Mobile gesendet

 ...

Empty body

Hi Sven,

I wonder what is being measured in "High_Impedanz_Voltage_plus_to_AC.bmp". The yellow voltage looks like the voltage in forward conduction across one of the diodes and the freewheeling flyback voltage of an inductor. The ground is then floating or the signal is inverted. The current looks like a 50Hz fully rectified AC signal being inverted but with its normal peak or top at ground level and the normal zero value being negative. If my guess is correct the yellow signal is the voltage between the cathode and anode of either D3 (ground at cathode of D3) or D4 (if ground is right hand side AC and common connection between D3 and D4). The time that this signal starts going negative is when the capacitor is fully charged. I.e. the flyback pulse of the inductor stops running. In the below image the signals are turned upside down for clarifying this. This also makes me realize that the magenta curve is the current from a saturating signal and not from a sine curve. The green boxes are the periods where D3 is conducting. The red curves are the periods where D1 is conducting and the capacitor is being charged from the AC source. This leaves no time without current going to the capacitor as the inductor is running in continuous mode. I.e. the inductor is never fully demagnetized. The green boxes represents the periods in time where no current is received from the input AC to the top half of the circuit.




Regards
Ole
 

---In [email protected], <s.friedrich@...> wrote :

 Hi Ole,
 
 I do not know how to write here it does not matter. I try it again by email:
 
 I can not get on with the diode plug and have just connected a FWBR s.der coupling capacitors and sometimes played with different loads and just times with the scope measured at various measuring points as the SCR stops working.
 
 I noticed that actually every diode plug must be charged twice before it triggers to think I work as Hector says. I hope he rectifies me.
 
 I've always wondered why he always thought to unload 30x SCR Minus and unload 30x SCR plus. There is a sine wave of 2 half-waves, if it is discharged each time, the value at 60Hz would be twice as high.
 
 I hope this message comes over otherwise I give it up.
 
 regards
 
 Sven   Gesendet: Donnerstag, 15. Februar 2018 um 03:41 Uhr
 Von: "onielsen@... [EVGRAY]" <[email protected]>
 An: [email protected]
 Betreff: Re: AW: Re: Aw: Re: AW: [EVGRAY] Re: buck plug ...
    
 Third time.
 
 Hi Sven,
 
 Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.
 
 The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.
 
 A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.
 
 Regards
 Ole
 
 
 ---In [email protected], <s.friedrich@...> wrote :
    
 Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven
  
 Von Samsung Mobile gesendet

 ...

Hi Sven,

I hope the images gets through this time. Else they're attached too.

I wonder what is being measured in "High_Impedanz_Voltage_plus_to_AC.bmp". The yellow voltage looks like the voltage in forward conduction across one of the diodes and the freewheeling flyback voltage of an inductor. The ground is then floating or the signal is inverted. The current looks like a 50Hz fully rectified AC signal being inverted but with its normal peak or top at ground level and the normal zero value being negative. If my guess is correct the yellow signal is the voltage between the cathode and anode of either D3 (ground at cathode of D3) or D4 (if ground is right hand side AC and common connection between D3 and D4). The time that this signal starts going negative is when the capacitor is fully charged. I.e. the flyback pulse of the inductor stops running. In the below image the signals are turned upside down for clarifying this. This also makes me realize that the magenta curve is the current from a saturating signal and not from a sine curve. The green boxes are the periods where D3 is conducting. The red curves are the periods where D1 is conducting and the capacitor is being charged from the AC source. This leaves no time without current going to the capacitor as the inductor is running in continuous mode. I.e. the inductor is never fully demagnetized. The green boxes represents the periods in time where no current is received from the input AC to the top half of the circuit.


PS. I don't know what is meant by 'to unload 30x SCR Minus and unload 30x SCR plus?'

Regards
Ole
 

---In [email protected], <s.friedrich@...> wrote :

 Hi Ole,
 
 I do not know how to write here it does not matter. I try it again by email:
 
 I can not get on with the diode plug and have just connected a FWBR s.der coupling capacitors and sometimes played with different loads and just times with the scope measured at various measuring points as the SCR stops working.
 
 I noticed that actually every diode plug must be charged twice before it triggers to think I work as Hector says. I hope he rectifies me.
 
 I've always wondered why he always thought to unload 30x SCR Minus and unload 30x SCR plus. There is a sine wave of 2 half-waves, if it is discharged each time, the value at 60Hz would be twice as high.
 
 I hope this message comes over otherwise I give it up.
 
 regards
 
 Sven   Gesendet: Donnerstag, 15. Februar 2018 um 03:41 Uhr
 Von: "onielsen@... [EVGRAY]" <[email protected]>
 An: [email protected]
 Betreff: Re: AW: Re: Aw: Re: AW: [EVGRAY] Re: buck plug ...
    
 Third time.
 
 Hi Sven,
 
 Here is one of your schematics which will do for describing an idea for peak detection. I hope this message doesn't get truncated.
 
 The current through the freewheeling diodes can be monitored by measuring the sign of the voltage across them. By watching when the voltage (U_pos) across D3 is negative this tells that the current through D1 has stopped and the stored energy of inductor L1 is being 'discharged' or actually demagnetized. When the inductor L1 is fully demagnetized the U_pos voltage stops being negative and the capacitor C1 is fully charged. This is the time for discharging C1 by triggering the T1 SCR.
 
 A similar circuit is used for triggering the negative cycle. By doing it this way the triggering point will always happen when the charging current to the capacitors stop flowing.
 
 Regards
 Ole
 
 
 ---In [email protected], <s.friedrich@...> wrote :
    
 Hello Ole, thank you for your comments. I would like to switch to the peak first, unfortunately, the circuit works together then I could imagine if I switch later, I get back to a clean sine wave without distortion. I would like to switch the voltage almost to zero a short peak, which is possible with reactive energy. By impedance reduction, of course, I can switch later or is it now only the impedance that makes it dependent? I think that I discharge the capacitors so now when the current is in zero crossing, otherwise the energy would be reflective to the load because additional current is charged into the capacitors. Greetings Sven
  
 Von Samsung Mobile gesendet

 ...

Hello Ole,

the yellow line is the tension. I'm not an engineer, I just could not understand what happened there. That's why I thought I'd make the circuit easier and observe the natural resonance without thyristors with the oscilloscope.

I have attached the circuit. Unfortunately, I did not have a proper shunt but an analog ammeter equipped with a shunt abused for it.

I just measured from DC plus to AC and DC minus the same and then this picture can be seen. I inverted the lower current curve.

Actually, the elaborate circuit of me is no longer like the new circuit. Just one FWBR each positive and negative charge a capacitor and 2 thyristors.

I really think that you can only discharge when the voltage goes to zero, and that only seems to be after every 2 positive half wave and negative half wave.

Hector always wrote from 30cps at 60cps. Actually we have 60 positive half-waves and 60 negative half-waves at 60cps.

I discovered another strange phenomenon. When in this simple circuit instead of incandescent lamps wanted to connect a transformer and had no proper contact there was a violent rollover. I was curious and then played with it, there was almost a 10mm long arc that melted my contacts. Of course, the transverter took up extra energy, but the fact that the small coupling capacitors can transfer so much energy was very impressive.

It's getting harder and harder to write here, sorry about the double mail.

regards

Sven

Hi Sven
 I could see those scope shots you put up very clear!
 Whatever you did this time, this is the way to post photos on EVGRAY message board.
 You can also go to files section here, and make a folder for yourself and upload photos and data and whatever you want into your own folder there....
 

 I have another yahoo "sister" group called EVGRAYTOOC that I like to upload stuff into, into their files  section there,  since EVGRAY files has so many files here...
 Also, two other sister sites - only made for more file space - and that is EVGRAYTOO and EVGRAYTOOB
 

 ciao
 Kone