Re: [EVGRAY] Re: J ² = 1

Database ID: 110591
2018-11-19T00:45:37+00:00
Warren Keillor <[email protected]>

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NormanThink how home computers and 3 D printers have changed the ease of building those clover leaf capacitors.You need to do a project book for kids to try building the simple stuff, using the technology that is now theirs. Enough of that trite shit like teddy bears, and vampire masks.Get the smart ones building stuff that matters..I remember my grade school best favourite book" the boy's book of model making" a printed in England, publication showing how to build steam engines, and pulse jet motors, with fold out pages of plans for real full sized projects.That was great for the early boomer era, but you get the idea.Later, the Whole Earth Catalog was the magic source.The Internet has been great, but we are losing it to jerks who just want power, and I don't mean energy.Politics, money, and religion have little in common with science, except they don't like people getting any ideas, that might topple their empires.Cheers Warren

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  On Sun, 18 Nov 2018 at 6:24 AM, Norman Wootan [email protected] [EVGRAY]<[email protected]> wrote:       
 

The principle of potential increase as the value of C is decreased was published by Charles Yost, Electric Space Craft Journal (RIP) as found in the Encyclopedia Britannica as an O/U device.  I built one of the variable capacitance devices, interleaved clover leaf capacitive plates just like the old air variable tuning capacitors in your Ham rigs.  The Hyde Generator works on the principle of voltage multiplication when C value is decreased.  Most devices use a variable inductor to accomplish the same phenomenon.
 
 On 11/17/2018 9:59 AM, An Hö [email protected] [EVGRAY] wrote:
  
    
Hi Ole,
 
  
 The imaginary part j or square root of -1 means reactive power. This has to be changed to active power without having to take active power from the source. A parametric change in capacitance ought to do this job as a decrease in capacitance at constant  charge means increase in energy.
  
 
   You mean 
   E = Q^2 / (2C) 
  ? I just re(did) the integration to see where this comes from. The above work had to be performed (energy spent) to get a specific Q into a cap. The above equation is valid for constant C during the charge phase only! Charging a cap to a given Q with decreasing C requires extra energy as can easily be seen in the following equation: 
   W = Integral (q / C) dq 
  So we already had to do extra work to get the cap with the decreasing capacitance charged. Let’s assume we have some C charged to some Q now. How could the C further be decreased (after disconnecting the voltage supply)? The only way I see is by increasing the distance between the plates but this requires mechanical work!?  
  I don’t see the potential for FE in this. It may theoretically be possible if we could 
  • charge the cap at constant C • then after disconnecting the power supply (constant Q) decrease the capacitance without having to apply mechanical work • then discharge into a load 
  But these are many Ifs!? Where is the apparatus/concept that can do this. I see no potential at all! :-( Am I missing anything? 
  Thanks, 
   Andreas 
  
  
  
  
   
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