Re: [EVGRAY] Re: J ² = 1

Database ID: 110567
2018-11-18T05:23:09-06:00
Norman Wootan <[email protected]>

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The principle of potential increase as the value of C is decreased was 
published by Charles Yost, Electric Space Craft Journal (RIP) as found 
in the Encyclopedia Britannica as an O/U device.  I built one of the 
variable capacitance devices, interleaved clover leaf capacitive plates 
just like the old air variable tuning capacitors in your Ham rigs.  The 
Hyde Generator works on the principle of voltage multiplication when C 
value is decreased.  Most devices use a variable inductor to accomplish 
the same phenomenon.

On 11/17/2018 9:59 AM, An Hö [email protected] [EVGRAY] wrote:
>
> Hi Ole,
>
>
>> The imaginary part j or square root of -1 means reactive power. This 
>> has to be changed to active power without having to take active power 
>> from the source. A parametric change in capacitance ought to do this 
>> job as a decrease in capacitance at constant charge means increase in 
>> energy.
>
> You mean
>
> E = Q^2 / (2C)
>
> ? I just re(did) the integration to see where this comes from. The 
> above work had to be performed (energy spent) to get a specific Q into 
> a cap. The above equation is valid for constant C during the charge 
> phase only! Charging a cap to a given Q with decreasing C requires 
> extra energy as can easily be seen in the following equation:
>
> W = Integral (q / C) dq
>
> So we already had to do extra work to get the cap with the decreasing 
> capacitance charged. Let’s assume we have some C charged to some Q 
> now. How could the C further be decreased (after disconnecting the 
> voltage supply)? The only way I see is by increasing the distance 
> between the plates but this requires mechanical work!?
>
> I don’t see the potential for FE in this. It may theoretically be 
> possible if we could
>
> • charge the cap at constant C
> • then after disconnecting the power supply (constant Q) decrease the 
> capacitance without having to apply mechanical work
> • then discharge into a load
>
> But these are many Ifs!? Where is the apparatus/concept that can do 
> this. I see no potential at all! :-( Am I missing anything?
>
> Thanks,
>
>  Andreas
>
>
>
>
>
>

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Subject Re: [EVGRAY] Re: J ² = 1
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