Re: [EVGRAY] Re: J ² = 1

Body

Hi Ole,

> The imaginary part j or square root of -1 means reactive power. This has to be changed to active power without having to take active power from the source. A parametric change in capacitance ought to do this job as a decrease in capacitance at constant charge means increase in energy.

You mean

	E = Q^2 / (2C)

? I just re(did) the integration to see where this comes from. The above work had to be performed (energy spent) to get a specific Q into a cap. The above equation is valid for constant C during the charge phase only! Charging a cap to a given Q with decreasing C requires extra energy as can easily be seen in the following equation:

	W = Integral (q / C) dq

So we already had to do extra work to get the cap with the decreasing capacitance charged. Let’s assume we have some C charged to some Q now. How could the C further be decreased (after disconnecting the voltage supply)? The only way I see is by increasing the distance between the plates but this requires mechanical work!? 

I don’t see the potential for FE in this. It may theoretically be possible if we could

• charge the cap at constant C
• then after disconnecting the power supply (constant Q) decrease the capacitance without having to apply mechanical work
• then discharge into a load

But these are many Ifs!? Where is the apparatus/concept that can do this. I see no potential at all! :-( Am I missing anything?

Thanks,

 Andreas