Re: J ² = 1

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2018-11-17T13:25:13+00:00

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So the battery say a + 12.7 VDC one as seen from 4D perspective within a resonance tank fed by a diode bridge has  got a value of  -12.7  or J 12.7  that substracts as jX  from the resonant tank that sees it as LOADING  R (- resistance ) contrary to its impedance Z .... so it results in a phasor loading to the source increasing power factor and power usage into the useless dimension ( wasted power). 

see varactor diode tuning principles as they apply perfectly  mentioned a million times in my old postings !

see -1 =  (J) relation to varactor diode tuning ,,,  

(translated from alien language to earth monkey one )

awaiting feedback //

as customary this material is a public disclosure from 

Hector Perez Torres  © 1998,2018   ARK Research Ω

not for sale and or use without reference to source not for patent or thesis papers .   

(H)  

  


---In [email protected], <arkresearch@...> wrote :

 Want to know how to neutralize the series loss of a battery voltage drop NEGATIVE VOLTAGE into the positive ?  and have a leading Power factor low loss resonance ? 

( Lets get together and built the freaking R&D lab !!!! )  the post  title is one of the formulas required to explain it ! 
and  yess ! its a freaking negative number  ! 

(H)

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