Re: [EVGRAY] Re: https://www.youtube.com/watch?v=RMYo1QlvK5g (Newman motor)

Body

JamesI keep wondering about that but have no decisive information regarding it.Zilano laid out specs for coils she made, and much like Tesla coils people build, it seems that high voltage goes through fine wire, and the big amp L2 is fat wire, wound in two different directions, picks up by induction, amps.Cheers Warren

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  On Sat, 12 Jan 2019 at 5:42 AM, James Glinski [email protected] [EVGRAY]<[email protected]> wrote:       
I think the finer the wire the more magnetic force and by shifting the wattage of amps by volts to hi voltages and very little amps you get more power and more back emf .

On Friday, January 11, 2019, [email protected] [EVGRAY] <[email protected]> wrote:


     
Hi Hector,

That link is the Joseph Newman motor. It seems to be draining the battery of 60 x 9V pretty fast.
https://youtu..be/RMYo1QlvK5g? t=524 8:44 minutes into the video the motor is running.
https://youtu.be/RMYo1QlvK5g? t=1114 18:34 minutes into the video the motor has slowed down after running for 10 minutes. It looks like the battery is being drained fast.

Looking at the pump it doesn't look like much power being delivered from the motor. The water is flowing at low pressure. Newman ought to do some proper measurements. If reading his book it can be seen that his motor use pulses. His multimeters aren't optimized for measuring pulses which gives false readings. I don't think his motor is more efficient than other high efficient motors like perhaps brushless DC motors or ironless DC motors.

If the pump lifts one m^3 of water (=1000 kg =2205 lb) to a height of 1m it takes 1000kg x 9.807m/s^2 x 1m = 9.807kJ of energy. If that is done in one minute the power required is (9.807kJ / 60s) = 163W.
With 60 batteries of 9V in series the voltage of the battery becomes:
9V x 60 = 540V.

If the power consumption is 163W the current at 540V is then 163W / 540V = 0.3A.
If the battery is rated at 550 mAh (https://wiki2.org/en/Nine- volt_battery#Technical_ specifications) it should deliver that power for almost two hours: 0.55Ah / 0.3A.= 1.8h.

Regards
Ole



---In [email protected], <arkresearch@...> wrote :


https://www.youtube.com/watch? v=RMYo1QlvK5g



   
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