Re: [EVGRAY] Re: https://www.youtube.com/watch?v=RMYo1QlvK5g (Newman motor)

Body

I think the finer the wire the more magnetic force and by shifting the
wattage of amps by volts to hi voltages and very little amps you get more
power and more back emf .

On Friday, January 11, 2019, [email protected] [EVGRAY] <
[email protected]> wrote:

>
>
> Hi Hector,
>
> That link is the Joseph Newman motor. It seems to be draining the battery
> of 60 x 9V pretty fast.
> https://youtu.be/RMYo1QlvK5g?t=524 8:44 minutes into the video the motor
> is running.
> https://youtu.be/RMYo1QlvK5g?t=1114 18:34 minutes into the video the
> motor has slowed down after running for 10 minutes. It looks like the
> battery is being drained fast.
>
> Looking at the pump it doesn't look like much power being delivered from
> the motor. The water is flowing at low pressure. Newman ought to do some
> proper measurements. If reading his book it can be seen that his motor use
> pulses. His multimeters aren't optimized for measuring pulses which gives
> false readings. I don't think his motor is more efficient than other high
> efficient motors like perhaps brushless DC motors or ironless DC motors.
>
> If the pump lifts one m^3 of water (=1000 kg =2205 lb) to a height of 1m
> it takes 1000kg x 9.807m/s^2 x 1m = 9.807kJ of energy. If that is done in
> one minute the power required is (9.807kJ / 60s) = 163W.
> With 60 batteries of 9V in series the voltage of the battery becomes:
> 9V x 60 = 540V.
>
> If the power consumption is 163W the current at 540V is then 163W / 540V =
> 0.3A.
> If the battery is rated at 550 mAh (https://wiki2.org/en/Nine-
> volt_battery#Technical_specifications) it should deliver that power for
> almost two hours: 0.55Ah / 0.3A.= 1.8h.
>
> Regards
> Ole
>
>
> ---In [email protected], <arkresearch@...> wrote :
>
> https://www.youtube.com/watch?v=RMYo1QlvK5g
>
> 
>