Re: [EVGRAY] Re: Moonbounce

Body

Ole,

Specifically the math is messing with my head.  Either I am
misunderstanding / applying the math else according to FPL calculations
antenna gain and dbW something the distance of the moon should not be
feasible without millions of watts of transmitter power.

Laserbounce is another story due to the reflectors and the fact a laser
stays colimated enough not to disperse as quickly as does Rf.


On 6/6/2018 3:04 PM, [email protected] [EVGRAY] wrote:
>  
>
> Hi Mick,
>
> The problem by using the moon as a reflector could be made more
> efficient if placing a RF reflector just like the LASER reflectors
> already out there. Another way could be making a RF repeater like is
> done in communication satellites. It would probably be much cheaper to
> put up a communication satellite or to use one of the many already up
> there.
>
> The surface of the moon isn't a good conductor (I guess) and it may
> even spread out the signal instead of reflecting it back to the
> transmitter like it is done withcorner reflectors
> <https://wiki2.org/en/Corner_reflector>. This gives great loss of the
> received signal.
>
> Regards
> Ole
>
>
>
> ---In [email protected], <mkjekyll@...> wrote :
>
> https://www.electronics-notes.com/articles/ham_radio/amateur-propagation/moonbounce-propagation-eme.php
>
> Here is a link for ham radio folk about EME or moonbounce radio.  The
> path loss in best case scenarios is very high.
>
>
> Can someone who knows more RF electronics theory such as Ole or Hector
> please comment as to how this is overcome with 1000 watt input
> transmitter when the maximum theoretical S/N ratio and 252 db PL
> should require transmitters larger than AM radio stations.
>
>
> I must be missing something.  Also checking the amateur radio sites
> for an answer.
>
>
>
> Thanks,
>
> Mick
>
>
>
>