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Hi Sven,
For transformation between output to load impedance the ratio of the transformer has to fit the impedance ratio to be able to do its job. Else the output voltage and impedance must be chosen to fit the load voltage and impedance or vice versa.
Or the load has to be disconnected from the capacitors even when the capacitors haven't fully discharged which gives the problem of switching off the SCRs. A load that can absorb the energy before the next charging cycle requires the proper resistance for the capacitance value chosen. This resistance can be calculated when the other parameters of the circuit are known. The other circuit parameters can also be calculated for a given load and worked backwards if the load is known as everything affects each other.
"I have already considered whether to connect the secondary coil of the push-pull transformer with a FWBR and conducts the energy in a mains choke and then connect in the battery with flyback diode as a step-down converter with only 50 Hz or 2x 230V / 24V transformers in parallel to the secondary winding to lower the impedance."
Or use a power resistor to dissipate the excess power as heat. This can transfer the energy of the capacitors into heat at almost any rate when correct chosen. The series inductance will be what limits the current and thus must be small enough to be able to discharge the capacitors fast enough to turn off the SCRs before the next capacitor charging. This power resistor can be added in parallel to make the load impedance less or in series to make it greater.
Regards
Ole
---In [email protected], <s.friedrich@...> wrote :
Hi Ole,
you just have to create a low impedance at the push-pull transformer. The problem is that this transformer is just a isolating transformer so the voltage is not down-converted to 24 volts.
The 230/24 volt transformers I have to connect to the secondary side of the pushpull generates a higher impedance which ensures longer switching times at the SCR.
I have already considered whether to connect the secondary coil of the push-pull transformer with a FWBR and conducts the energy in a mains choke and then connect in the battery with flyback diode as a step-down converter with only 50 Hz or 2x 230V / 24V transformers in parallel to the secondary winding to lower the impedance.
The only question is when the 24V winding is connected with a FWBR to the battery, the battery will act against it with its own voltage and create additional impedance in the push-pull transformer.
The easiest way would be to connect the secondary winding directly to the battery and to charge it with the energy peaks.
I'm just not comfortable because the batteries are in excellent condition and I do not want to destroy them.
regards
Sven