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Hi Sven,
I think that zero Ohm is meant as the resonant frequency of an LC-tank where the capacitive reactance cancels the inductive reactance. Only the resistive part remains which is the resistance of the conductors. This resistive part can be made smaller by using thicker wires and capacitors having thicker foils or copper foil instead of aluminum foil. But first make it work before going to the extreme which is also quite expensive. I don't think anybody needs that high efficiency except perhaps military researchers or other state financed researchers.
If not returning the power back to the source it is no longer reactive. Reactive power is when the energy sloshes back and forth between two points. This way the energy isn't consumed or dissipated to somewhere else like heating the ambient. Active power travels in one direction by not giving back the energy to its source.
Regards
Ole
---In [email protected], <s.friedrich@...> wrote :
Hi Ole,
From a conventional point of view, it makes no sense for me to switch to 0 ohms, it's a simple short circuit, destroying the switches and delivering no usable energy.
We have a main LC (three-phase transformer) that generates reactive power, which we transfer via coupling capacitors to the diode plug. Two diodes split the positive and the negative half-wave into a half-LC.
So far so good. The diodes are not the problem because I can also switch reactive power through a FWBR without noticeable losses, that's how I see it.
Further, when this half LC is charged, it must perfectly re-enter the main LC so that it consumes no additional active power.
What does it look like based on a reactive window in which time does the energy have to be transferred? It is not enough to discharge the capacitor in time, the coil of the push-pull transformer must not deliver any magnetic energy in the direction.
Unfortunately, the fact is that I apply energy for reactive power and again the same when switching the thyristors and the later I discharge the thyristors the more active power I use in addition. If I increase the load secondary, the input energy decreases slightly.
If you reach the point where only the energy for the reactive power must be applied and a few watts for the switches then we are a long way further.
The transformer is quite big with 6.3 kva but it also has a fairly small inductance, you still have room on your thighs, you could now apply additional windings that further negate the inductance, but then I also transfer less energy or see that wrong. The high-inductive 230 / 24V transformer I do not need to connect directly because the inductance is so high, there is only a single switch and the energy dies, even if I short-circuit it on the secondary side.
The only element I know with an extremely low resistance are batteries that I have only 11 milli ohms although they are not very big, but I can not pop such discharges directly into a 24 volt battery right?!?
I try on different contacts such as diodes, push-pull-transformer, thyristor, etc. to make a scope picture maybe even a video if it's worth it.
regards
Sven