Body
Hi Ole, I meant that with the Scope different I'm looking for the point exactly when unloading and no energy in the LC from Pushpull trafo can be delivered. I just read in the re ou 6.1 pdf which theoretically at 0 ohms the energy is infinite. 0 ohm does not convert any power and my thyristors break down. You have to recognize the LC curve where you have to engage or switch at the wrong time? Greetings Sven
Von Samsung Mobile gesendet
-------- Ursprüngliche Nachricht --------
Von: "[email protected] [EVGRAY]" <[email protected]>
Datum:13.02.2018 01:11 (GMT+01:00)
An: [email protected]
Betreff: [EVGRAY] Re: buck plug ...
Hi Sven,
"Is there a way to visualize the energy consumed by scope in the primary winding so that you can see that the energy needs to be consumed faster."
Yes if the scope can calculate the power and then integrate the power. Alternatively the energy in a an inductor is given by this formula:
where E is the energy in Joule (or Ws). L is the inductance in Henry and U is the voltage in Volt. Knowing this the energy can be calculated at any given instant by knowing the current through the inductor at that particular moment..
If calculating the power by multiplying the current with the tension and the power is constant the energy can be calculated by multiplying the time with the constant power. As power is the rate of energy transfer energy equals power multiplied by time when the power is held constant or E = P_constant x T [Joule = Watt_constant x second]. No change in Watt is allowed if using this linear formula.
Transferring the energy to a capacitor through a rectifier is also a way to calculate the energy stored. The energy stored in a capacitor can be calculated by knowing its capacitance and the voltage across it.
Regards
Ole
---In [email protected], <s.friedrich@...> wrote :
Hello to all interested,
I've tried a large load on the push pull transformer to lower the impedance even a DC motor I plugged in, you could really see how the recorded power diminished on the meter. About 30 watts less, but still I needed additional active power than with pure resonance when I operate the diode plug.
It is really difficult, even the negative diode plug makes more and more like the positive diode plug, I have already tested other capacitors, discharge capacitors coupling capacitors, the values reversed it always stays there.
I measure with the scope on both capacitors simultaneously.
Is there a way to visualize the energy consumed by scope in the primary winding so that you can see that the energy needs to be consumed faster.
I had a new drawing uploaded to lower the primary coil impedance moderately directly at least at idle. Maybe you can also bring the thyristor for quicker shutdown, the capacitors are then not fully discharged but the energy can then be discharged depending on the impedance behavior of the secondary coil longer or shorter. If the primary coil is fully charged and no power is dissipated, a capacitor could be charged via a freewheeling diode so the capacitor would form an antipole and cancel the potential difference and the thyristor will turn off immediately. If I did not make a mistake.
regards
Sven
https://youtu.be/UY8pceAjm_E