Re: [EVGRAY] Re: Triple thick BiTT

Body

Hi Kone,

The current written on the lamp is at 12V AC. Without knowing the characteristics of the lamp there is no way of knowing the actual current. It also reads 3W but this is also at 12V. So which one is correct at 16.95V if any one of them?!

I think this is what it says on the LED lamp:
3W 3000K
12V 50-60Hz 360mA
4GU5.3MR16-C
Made in China
Fabrique en China

If the lamp dissipates 3W it uses 4.32VA (= 12V X 360mA) apparent power having a cosine to the phase angle of 3W/4.32VA = 0.69.

Here are some lamps getting close to this one:
https://www.amazon.de/M%C3%BCller-Licht-Reflektor-GU5-3-Energieeffizienzklasse-56025/dp/B00EHFYRO4 https://www.amazon.de/M%C3%BCller-Licht-Reflektor-GU5-3-Energieeffizienzklasse-56025/dp/B00EHFYRO4

https://www.pearl.de/a-NX2604-3303.shtml;jsessionid=kE13E6B9CF03296E32DBCF9C4C4B367B3 https://www.pearl.de/a-NX2604-3303.shtml;jsessionid=kE13E6B9CF03296E32DBCF9C4C4B367B3

But no datasheet showing the electrical characteristics. Is it constant power or constant current or are both variables depending on each other as per Ohm's and Watt's laws?

Conclusion is that it's hard to know anything about the load without a proper measurement when using a nonlinear load as LEDs are as well as if the lamp has its own regulator or it doesn't.

Regards
Ole 

---In [email protected], <konehead@...> wrote :

 Hi Warren
 Actually it is 360ma that his bulb shows written on the base, and 12Vdc.......
 So if 16.92V (not approx. 18 like I wrote) that comes to 16.95Vdc X .36A =
 6.1 Watts output compared to the .39 X 12V input of 4.68Watts
 I just assumed that is an LED, I don't know! maybe it is not and all the LED characteristics of over-voltage and what happens to current  just do not matter....
 He uses what looks like four LEDs he says of 3W each in his other video, to get a 12W load these look smaller but do not know for sure...
 ciaoKone