EVGRAY Archive

Re: AC to Cap Dump

Database ID: 104997
2017-12-05T06:29:50+00:00
hob.nilre <[email protected]>

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Hi Ole,

Power out is simply Vbat²/R where Vbat is the voltage across the battery and R is the dump-resistor.

Power in is Vbat*f*C*(Vcap-Vbat) where f is the AC frequency, 50Hz where I am, and Vcap is the voltage across the cap just before the dump to the battery and C is the capacitance of the cap. C*(Vcap-Vbat) is the charge Q being dumped from the cap as in Q = C*V and so f*Q is the total charge during a second which in turn is the average current. Work done is Vbat*Q which for one second is the same as the avg power.

Does it make sense or am I making a mistake somewhere?

/Hob

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Subject Re: AC to Cap Dump
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